Thread overview
package access specifier not usable within a class
Sep 09, 2011
Andrej Mitrovic
Sep 09, 2011
Christophe
Sep 09, 2011
Christophe
Oct 27, 2011
SourceCode
September 09, 2011
abstract class Foo
{
    package void test();
}

class Bar : Foo
{
    override package void test() { }
}

function test.Bar.test cannot override a non-virtual function

TDPL says package can only be used at class-level (i.e. package class Bar : Foo), outside classes or inside a struct.

I want to hide a virtual method from client code, but another free function in a different module but in the same package as these classes needs access to that method. Are there any technical reasons why package is not allowed for virtual methods?
September 09, 2011
Andrej Mitrovic , dans le message (digitalmars.D.learn:29388), a écrit :
> abstract class Foo
> {
>     package void test();
> }
> 
> class Bar : Foo
> {
>     override package void test() { }
> }
> 
> function test.Bar.test cannot override a non-virtual function
> 
> TDPL says package can only be used at class-level (i.e. package class Bar : Foo), outside classes or inside a struct.
> 
> I want to hide a virtual method from client code, but another free function in a different module but in the same package as these classes needs access to that method. Are there any technical reasons why package is not allowed for virtual methods?

private function are not virtual.
"All non-static non-private non-template member functions are virtual"
The spirit of this is that if a function is private, it should not be
seen by its subclasses, which makes sens. However, this is a bit
inconsistent with the fact that it can actually be seen by the whole
file. It seems that package function inherited from the same behavior,
enlarging this inconsistency.

Your request seem to be reasonable, so I would say the langage should be
improved in two ways:
- private (and package) function can be specifically made virtual, but
the problem is that virtual is not a keyword in d, and that would be
weird to have to write final sometimes, and virtual some other times.
- package function are virtual by default, which is the best solution
IMO. It's not a huge problem if private methods cannot be virtual, if
you can make them package virtual.

In the meantime, I would make the method public, but prefix the name with an underscore to indicate it is morally private. I agree that it is relying on the client's good will.

-- 
Christophe
September 09, 2011
Christophe, dans le message (digitalmars.D.learn:29394), a écrit :
> Andrej Mitrovic , dans le message (digitalmars.D.learn:29388), a écrit :
>> abstract class Foo
>> {
>>     package void test();
>> }
>> 
>> class Bar : Foo
>> {
>>     override package void test() { }
>> }
>> 
>> function test.Bar.test cannot override a non-virtual function
>> 
>> TDPL says package can only be used at class-level (i.e. package class Bar : Foo), outside classes or inside a struct.
>> 
>> I want to hide a virtual method from client code, but another free function in a different module but in the same package as these classes needs access to that method. Are there any technical reasons why package is not allowed for virtual methods?
> 
> private function are not virtual.
> "All non-static non-private non-template member functions are virtual"
> The spirit of this is that if a function is private, it should not be
> seen by its subclasses, which makes sens. However, this is a bit
> inconsistent with the fact that it can actually be seen by the whole
> file. It seems that package function inherited from the same behavior,
> enlarging this inconsistency.
> 
> Your request seem to be reasonable, so I would say the langage should be
> improved in two ways:
> - private (and package) function can be specifically made virtual, but
> the problem is that virtual is not a keyword in d, and that would be
> weird to have to write final sometimes, and virtual some other times.
> - package function are virtual by default, which is the best solution
> IMO. It's not a huge problem if private methods cannot be virtual, if
> you can make them package virtual.
> 
> In the meantime, I would make the method public, but prefix the name with an underscore to indicate it is morally private. I agree that it is relying on the client's good will.
> 
> -- 
> Christophe

I forgot about protected. Making the function protected may be fine.
October 27, 2011
But what if i had something like this:

abstract class A {
package:
   abstract void _test() const;
}

class B : public A {
package:
    override void _test() const { writeln("Call B::test"); }
}

class C {
public:
    void do_something(const B b) {
        b._test();
    }
}

That only work if i define the method public. But Imo that must work, because that is imo the correct use of package.