http://d.puremagic.com/issues/show_bug.cgi?id=10262

           Summary: utf.decodeFront doesn't work with a string slice
           Product: D
           Version: D2
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody@puremagic.com
        ReportedBy: gdkslpmq@spam4.me


--- Comment #0 from Derek Rhodes <gdkslpmq@spam4.me> 2013-06-04 00:34:58 PDT ---
The code

import std.utf;

void main() {
    string str = "asdf";
    size_t size;

    decodeFront(str[1..$], size);
}

fails to compile, with the error

test.d(8): Error: template std.utf.decodeFront does not match any function
template declaration. Candidates are:
/usr/include/d/std/utf.d(978):        std.utf.decodeFront(S)(ref S str, out
size_t numCodeUnits) if (!isSomeString!(S) && isInputRange!(S) &&
isSomeChar!(ElementType!(S)))
/usr/include/d/std/utf.d(1012):        std.utf.decodeFront(S)(ref S str, out
size_t numCodeUnits) if (isSomeString!(S))
/usr/include/d/std/utf.d(1038):        std.utf.decodeFront(S)(ref S str) if
(isInputRange!(S) && isSomeChar!(ElementType!(S)))
/usr/include/d/std/utf.d(978): Error: template std.utf.decodeFront cannot
deduce template function from argument types !()(string, ulong)

Casting str[1..$] to a string explicitly results in the same error. Putting the slice outside the function call, like

string s2 = str[1..$];
decodeFront(s2, size);

Fixed the error.

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Jonathan M Davis <jmdavisProg@gmx.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |jmdavisProg@gmx.com
         Resolution|                            |INVALID


--- Comment #1 from Jonathan M Davis <jmdavisProg@gmx.com> 2013-06-04 00:50:53 PDT ---
It's not supposed to work with a slice like that. It accepts arguments by ref and pops off elements from the range that it's given, so it requires that you give it an lvalue, which is what you did with

string s2 = str[1..$];
decodeFront(s2, size);

It accepted rvalues in 2.062, but that resulted in very inconsistent and potentially buggy behavior (depending on the type of range), so it now accepts the range by ref.

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--- Comment #2 from Derek Rhodes <gdkslpmq@spam4.me> 2013-06-04 00:59:47 PDT ---
Ah sorry, my mistake.

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