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August 20, 2013 Struct - static initialization "on-the-fly" | ||||
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In this program:
import std.stdio, std.json;
void main () {
JSONValue jsonSet;
jsonSet.type = JSON_TYPE.OBJECT;
JSONValue a = { type: JSON_TYPE.STRING, str: "abcde" }; // This work
jsonSet.object["a"] = a;
jsonSet.object["b"] = { type: JSON_TYPE.STRING, str: "jjf" }; // THIS LINE
}
marked line will not compile failing with:
json.d(8): Error: found ':' when expecting ';' following statement
Is there any way to selectively initialize a struct while using it as AA value? The way I set "a" key works, but requires two lines instead of one and I have many such elements to set. I can't initialize all members of JSONValue, because there are many and I only need those two.
--
Marek Janukowicz
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August 20, 2013 Re: Struct - static initialization "on-the-fly" | ||||
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Posted in reply to Marek Janukowicz | On 08/20/2013 03:47 PM, Marek Janukowicz wrote:> In this program: > > import std.stdio, std.json; > > void main () { > JSONValue jsonSet; > jsonSet.type = JSON_TYPE.OBJECT; > JSONValue a = { type: JSON_TYPE.STRING, str: "abcde" }; // This work > jsonSet.object["a"] = a; > jsonSet.object["b"] = { type: JSON_TYPE.STRING, str: "jjf" }; // THIS LINE > } > > marked line will not compile failing with: > json.d(8): Error: found ':' when expecting ';' following statement > > Is there any way to selectively initialize a struct while using it as AA > value? The way I set "a" key works, but requires two lines instead of one > and I have many such elements to set. I can't initialize all members of > JSONValue, because there are many and I only need those two. > Unfortunately, that syntax works only when initializing a variable. Would you like the following syntax instead? root.object["a"] = to!JSONValue("abcde"); root.object["b"] = to!JSONValue("jjf"); If so, the following thread has a rough implementation of a 'to' specialization for JSONValue: http://forum.dlang.org/post/jl6bsn$67k$1@digitalmars.com Ali |
August 20, 2013 Re: Struct - static initialization "on-the-fly" | ||||
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Posted in reply to Ali Çehreli | Ali Çehreli wrote: > On 08/20/2013 03:47 PM, Marek Janukowicz wrote:> In this program: > > > > import std.stdio, std.json; > > > > void main () { > > JSONValue jsonSet; > > jsonSet.type = JSON_TYPE.OBJECT; > > JSONValue a = { type: JSON_TYPE.STRING, str: "abcde" }; // This work > > jsonSet.object["a"] = a; > > jsonSet.object["b"] = { type: JSON_TYPE.STRING, str: "jjf" }; // > THIS LINE > > } > > > > marked line will not compile failing with: > > json.d(8): Error: found ':' when expecting ';' following statement > > > > Is there any way to selectively initialize a struct while using it as > > AA value? The way I set "a" key works, but requires two lines instead > > of one and I have many such elements to set. I can't initialize all > > members of JSONValue, because there are many and I only need those two. > > > > Unfortunately, that syntax works only when initializing a variable. Too bad :( Is there any specific reason for that or is that just not implemented (yet)? > Would you like the following syntax instead? > > root.object["a"] = to!JSONValue("abcde"); > root.object["b"] = to!JSONValue("jjf"); > > If so, the following thread has a rough implementation of a 'to' specialization for JSONValue: > > http://forum.dlang.org/post/jl6bsn$67k$1@digitalmars.com Yes, this fulfills my "single line" requirement, thanks! -- Marek Janukowicz |
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