Hi :)

I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum:

2.97506e+,12

How I can make to get the correctly representation of this number ?

PS: that is my code:

import std.stdio, std.algorithm, std.range, std.conv;

string InsertComma(string val)
{
	return val[0 .. $-2] ~ "," ~ val[$-2 .. $];
}

int main(string[] argv)
{
	auto x = "oi.txt"
		.File
		.byLine
		.filter!(line => line[0] == '1')
		.map!(line => line[127 .. 140].to!real)
		.sum;

	auto valor = to!string(x);

	write(InsertComma(valor));

	readln();
     return 0;
}


On Thursday, 10 July 2014 at 17:16:01 UTC, Alexandre wrote:
> Hi :)
>
> I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum:
>
> 2.97506e+,12
>
> How I can make to get the correctly representation of this number ?

On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:

> Hi :)
> 
> I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum:
> 
> 2.97506e+,12
> 
> How I can make to get the correctly representation of this number ?

A full decimal representation can be gotten with `format("%f", n);`

On Thu, 10 Jul 2014 17:17:40 +0000, Justin Whear wrote:

> On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:
> 
>> Hi :)
>> 
>> I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum:
>> 
>> 2.97506e+,12
>> 
>> How I can make to get the correctly representation of this number ?
> 
> A full decimal representation can be gotten with `format("%f", n);`

And if you need more than the default 6 digits of precision after the decimal, you can use a precision specifier, e.g. for 10 digits: `format ("%.10f", n)`