Thread overview
Alias this and std.traits.isArray
Jan 05, 2013
David
Jan 05, 2013
monarch_dodra
Jan 06, 2013
Jonathan M Davis
Jan 06, 2013
David
Jan 06, 2013
Philippe Sigaud
Jan 09, 2013
David
Jan 09, 2013
Philippe Sigaud
January 05, 2013
This code worked with dmd 2.060:

import std.stdio;
import std.traits;

struct OhWhy(S) {
    S[] arr;
    alias arr this;
}

void main() {
	static assert(isArray!(OhWhy!(float)));

}

But fails with dmd 2.061:
ss.d(10): Error: static assert  (isArray!(OhWhy!(float))) is false

(same happens with alias this to static arrays and isArray/isStaticArray)


Is this intended or a regression? If latter, I'll submit a bug-ticket.
January 05, 2013
On Saturday, 5 January 2013 at 14:43:49 UTC, David wrote:
> This code worked with dmd 2.060:
>
> import std.stdio;
> import std.traits;
>
> struct OhWhy(S) {
>     S[] arr;
>     alias arr this;
> }
>
> void main() {
> 	static assert(isArray!(OhWhy!(float)));
> 	
> }
>
> But fails with dmd 2.061:
> ss.d(10): Error: static assert  (isArray!(OhWhy!(float))) is false
>
> (same happens with alias this to static arrays and isArray/isStaticArray)
>
>
> Is this intended or a regression? If latter, I'll submit a bug-ticket.

All traits in std trait of the type were explicitly changed to return true only if *the exact type* meets the traits requirement.

The rationale is simply tha OhWhy isn't an array. It can be implicitly cast to array, but it isn't an array.

This is problematic when instanciating template functions with automatic type inference: when you write "myTemplateFunction(myOhWhy)", then you will instanciate "myTemplateFuction!OhWhy" when what you may have wanted was to actually call "myTemplateFunction!(S[])".

The new "isArray" definition protects from that.
January 06, 2013
On Saturday, January 05, 2013 22:57:51 monarch_dodra wrote:
> On Saturday, 5 January 2013 at 14:43:49 UTC, David wrote:
> > This code worked with dmd 2.060:
> > 
> > import std.stdio;
> > import std.traits;
> > 
> > struct OhWhy(S) {
> > 
> >     S[] arr;
> >     alias arr this;
> > 
> > }
> > 
> > void main() {
> > 
> > 	static assert(isArray!(OhWhy!(float)));
> > 
> > }
> > 
> > But fails with dmd 2.061:
> > ss.d(10): Error: static assert  (isArray!(OhWhy!(float))) is
> > false
> > 
> > (same happens with alias this to static arrays and
> > isArray/isStaticArray)
> > 
> > 
> > Is this intended or a regression? If latter, I'll submit a bug-ticket.
> 
> All traits in std trait of the type were explicitly changed to return true only if *the exact type* meets the traits requirement.
> 
> The rationale is simply tha OhWhy isn't an array. It can be implicitly cast to array, but it isn't an array.
> 
> This is problematic when instanciating template functions with automatic type inference: when you write "myTemplateFunction(myOhWhy)", then you will instanciate "myTemplateFuction!OhWhy" when what you may have wanted was to actually call "myTemplateFunction!(S[])".
> 
> The new "isArray" definition protects from that.

Exactly. The std.traits traits are testing for exact types. If you want to test for implicit conversion, then use the : operator. e.g.

    static assert(is(OhWhy!float : float[]));

- Jonathan M Davis
January 06, 2013
Thanks for your answers, but:

> Exactly. The std.traits traits are testing for exact types. If you want to test for implicit conversion, then use the : operator. e.g.
> 
>     static assert(is(OhWhy!float : float[]));

"OyWhy" is a templated struct for a reason, I have no idea which type of array is "alias this'ed" is there a way I can check if it's implicitly convertable to any array type with some `is` magic I am not aware of?

January 06, 2013
On Sun, Jan 6, 2013 at 1:36 PM, David <d@dav1d.de> wrote:

> Thanks for your answers, but:
>
> > Exactly. The std.traits traits are testing for exact types. If you want
> to
> > test for implicit conversion, then use the : operator. e.g.
> >
> >     static assert(is(OhWhy!float : float[]));
>
> "OyWhy" is a templated struct for a reason, I have no idea which type of array is "alias this'ed" is there a way I can check if it's implicitly convertable to any array type with some `is` magic I am not aware of?
>
>
Like this?

struct MyType(Elem)
{
    Elem[] inner;
    alias inner this;
}

void main()
{
    static assert(is(MyType!float _ : T[], T));
}


January 09, 2013
> Like this?
> 
> struct MyType(Elem)
> {
>     Elem[] inner;
>     alias inner this;
> }
> 
> void main()
> {
>     static assert(is(MyType!float _ : T[], T));
> }
> 

And how does that work for a static array?
January 09, 2013
On Wed, Jan 9, 2013 at 10:57 PM, David <d@dav1d.de> wrote:
>> Like this?
>>
>> struct MyType(Elem)
>> {
>>     Elem[] inner;
>>     alias inner this;
>> }
>>
>> void main()
>> {
>>     static assert(is(MyType!float _ : T[], T));
>> }
>>
>
> And how does that work for a static array?

For a static array, the generic type is T[n], for some T and a size_t n. So:

static assert(is(MyType!float _ : T[n], T, size_t n));