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March 25, 2014 Lazy mixins | ||||
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mixin template A() { lazy mixin(B); //mixin(B); } template B() { string B() { return "void foo(double d) { foo(cast(int)d); }"; } } class C { void foo(int x) { writeln("x"); } mixin A; // tries to add foo to class but already exists(even though it is not identical) } without the lazy mixin in A, foo is created while the template is being "instantiated". Then in C, the mixin does not overload foo and hence does nothing(there is no foo(double) in C). If we can "lazily" evaluate the string mixin, then it would work(since string mixins do not do any overload analysis). That, or allow one to overload with mixin templates. i.e., the class C becomes class C { void foo(int x) { writeln("x"); } mixin(B); // because of lazy(which doesn't evaluate string mixins immediately) } I know it doesn't seem like much but it is. Because one can't simplify certain things(I can't get the this pointer under the hood in a string template which makes code generation difficult and requires extra code to get everything working). |
March 25, 2014 Re: Lazy mixins | ||||
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Posted in reply to Frustrated | That's probably not the solution you want, but could you use direct string mixins? import std.stdio; string B() { return `void foo(double d) { writeln("foo(double)"); }`; } class C { void foo(int x) { writeln("x"); } mixin(B()); } void main() { auto c = new C(); c.foo(1.3); } |
March 25, 2014 Re: Lazy mixins | ||||
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Posted in reply to Philippe Sigaud | On Tuesday, 25 March 2014 at 20:23:47 UTC, Philippe Sigaud wrote:
> That's probably not the solution you want, but could you use direct
> string mixins?
>
>
> import std.stdio;
>
>
> string B() { return `void foo(double d) { writeln("foo(double)"); }`; }
>
> class C
> {
> void foo(int x) { writeln("x"); }
> mixin(B());
> }
>
> void main() {
> auto c = new C();
> c.foo(1.3);
> }
No, I think I mentioned that string mixins can't get the context they are inserted in. Why would I simply wrap a string mixin around a template mixin if there wasn't some purpose that string mixins couldn't use in the first place?
For example, with a template mixin you can do this
mixin A;
while with a string mixin you have to do
mixin B!(typeof(this));
because A has the context of what it is inserted an you can use typeof(this) and it refers to the proper context. In B, there is no such context so it has to be passed requiring the user to always pass it. Hence string mixins can't do everything. The problem with template mixins is that they don't properly overload(only use the name to check, if it exists then it won't insert/overload).
Hence you can't do both. Use string mixins and you got to supply the argument. Use template mixins and you can't overload properly(which makes it useless in my case). If one could evaluate the string mixin after the template mixin then it would all work. (and yes, it is the solution I want unless you can actually come up with something that solves the problem directly(both overloads properly and allows one to get the context)
One can't do something like
template B(T = typeof(this))
{
}
which would also solve the problem(but string mixins don't inherit scope so it won't work).
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March 25, 2014 Re: Lazy mixins | ||||
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Posted in reply to Frustrated | On Tue, 25 Mar 2014 21:17:49 +0000, Frustrated wrote:
> Hence you can't do both. Use string mixins and you got to supply the argument. Use template mixins and you can't overload properly(which makes it useless in my case). If one could evaluate the string mixin after the template mixin then it would all work. (and yes, it is the solution I want unless you can actually come up with something that solves the problem directly(both overloads properly and allows one to get the context)
)
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March 26, 2014 Re: Lazy mixins | ||||
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Posted in reply to Frustrated | > No, I think I mentioned that string mixins can't get the context they are inserted in. Why would I simply wrap a string mixin around a template mixin if there wasn't some purpose that string mixins couldn't use in the first place? OK. I just preferred to ask, to be sure. > Hence you can't do both. Use string mixins and you got to supply the argument. Use template mixins and you can't overload properly(which makes it useless in my case). If one could evaluate the string mixin after the template mixin then it would all work. (and yes, it is the solution I want unless you can actually come up with something that solves the problem directly(both overloads properly and allows one to get the context) > > One can't do something like > > template B(T = typeof(this)) > { > > } Did you try using a this template parameter? |
March 26, 2014 Re: Lazy mixins | ||||
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Posted in reply to Philippe Sigaud | On Wednesday, 26 March 2014 at 04:05:10 UTC, Philippe Sigaud
wrote:
>> No, I think I mentioned that string mixins can't get the context they are
>> inserted in. Why would I simply wrap a string mixin around a template mixin
>> if there wasn't some purpose that string mixins couldn't use in the first
>> place?
>
> OK. I just preferred to ask, to be sure.
>
>> Hence you can't do both. Use string mixins and you got to supply the
>> argument. Use template mixins and you can't overload properly(which makes it
>> useless in my case). If one could evaluate the string mixin after the
>> template mixin then it would all work. (and yes, it is the solution I want
>> unless you can actually come up with something that solves the problem
>> directly(both overloads properly and allows one to get the context)
>>
>> One can't do something like
>>
>> template B(T = typeof(this))
>> {
>>
>> }
>
> Did you try using a this template parameter?
doesn't work. You can't use this in string mixins. There is no
context.
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