June 14, 2015 Re: how come is this legal? 'void fun(int){ }' ? | ||||
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Attachments: | On Sun, 14 Jun 2015 05:11:17 +0000, Maxim Fomin wrote:
> On Sunday, 14 June 2015 at 01:20:39 UTC, Timothee Cour wrote:
>> I understand this is legal for declaration wo definition (void
>> fun(int);)
>> but why allow this:
>> void test(int){} ?
>
> Actually it is void test(int _param_0) { }
> You can test by compiling void test(int) { _param_0 = 0; }
>
> Nameless parameters are simulated by providing internal symbol as above.
yet one shouldn't rely on generated names, they are undocumented on purpose, and can change without a notice and deprecation cycle.
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