How can you deep-copy a std.container.Array instance?

The actual array data is heap-allocated and reference-counted.
Assignment and .dup only create additional references.

Using a copy constructor yields an error:

Array!Foo x;
Array!Foo y = Array!Foo(x);

Error: template std.container.Array!(Foo).Array.__ctor cannot
deduce function from argument types !()(Array!(Foo)), candidates
are:
/opt/compilers/dmd2/include/std/container.d(2652):
std.container.Array!(Foo).Array.__ctor(U)(U[] values...) if
(isImplicitlyConvertible!(U, T))
/opt/compilers/dmd2/include/std/container.d(2670):
std.container.Array!(Foo).Array.__ctor(Stuff)(Stuff stuff) if
(isInputRange!Stuff &&
isImplicitlyConvertible!(ElementType!Stuff, T) && !is(Stuff ==
T[]))


The question came up in a reddit discussion:
http://www.reddit.com/r/programming/comments/2ipdpa/floss_weekly_311_the_d_language/cl4yv8w

On Thursday, 9 October 2014 at 21:14:46 UTC, qznc wrote:
> How can you deep-copy a std.container.Array instance?

Ok, the deep-copy problem already got resolved on reddit: Use dup.

However, the error is still open. You cannot give an Array!X
argument to constructor/replace/insertBefore of Array!X instances?

On Thursday, 9 October 2014 at 21:24:55 UTC, qznc wrote:
> On Thursday, 9 October 2014 at 21:14:46 UTC, qznc wrote:
>> How can you deep-copy a std.container.Array instance?
>
> Ok, the deep-copy problem already got resolved on reddit: Use dup.
>
> However, the error is still open. You cannot give an Array!X
> argument to constructor/replace/insertBefore of Array!X instances?

You will just need to slice it to provide a range.

On Friday, 10 October 2014 at 06:27:35 UTC, yazd wrote:
> On Thursday, 9 October 2014 at 21:24:55 UTC, qznc wrote:
>> On Thursday, 9 October 2014 at 21:14:46 UTC, qznc wrote:
>>> How can you deep-copy a std.container.Array instance?
>>
>> Ok, the deep-copy problem already got resolved on reddit: Use dup.
>>
>> However, the error is still open. You cannot give an Array!X
>> argument to constructor/replace/insertBefore of Array!X instances?
>
> You will just need to slice it to provide a range.

Like the following? That did not work.

Array!Foo y = Array!Foo(x[]);

>
> Like the following? That did not work.
>
> Array!Foo y = Array!Foo(x[]);

How does it not work?
It compiles successfully: http://dpaste.dzfl.pl/583d20e426a0

On Friday, 10 October 2014 at 10:32:17 UTC, yazd wrote:
>>
>> Like the following? That did not work.
>>
>> Array!Foo y = Array!Foo(x[]);
>
> How does it not work?
> It compiles successfully: http://dpaste.dzfl.pl/583d20e426a0

yeah man.

On Friday, 10 October 2014 at 10:59:59 UTC, Sag Academy wrote:
> On Friday, 10 October 2014 at 10:32:17 UTC, yazd wrote:
>>>
>>> Like the following? That did not work.
>>>
>>> Array!Foo y = Array!Foo(x[]);
>>
>> How does it not work?
>> It compiles successfully: http://dpaste.dzfl.pl/583d20e426a0
>
> yeah man.

You are right.

Sorry. I probably messed up my test file somehow.