Hello,

Suppose I have the following function

auto veryStableAPI(string parameter,VaraiadicParams...)() {
    // do something very slow and stable;
 ....
}

auto experimentalReplacement(string parameter,VaraidcParams ...)() {
 // do the same thing very fast and dangerous
}

is the following

auto veryStableAPI(bool brave=false, string parameter,VaraiadicParams...) {
 static if (!brave)
     // do something very slow and stable;
 else
     // do the same thing very fast and dangerous
}
valid according to spec ?

On Monday, 27 January 2014 at 19:56:05 UTC, Uplink_Coder wrote:
> Hello,
>
> Suppose I have the following function
>
> auto veryStableAPI(string parameter,VaraiadicParams...)() {
>     // do something very slow and stable;
>  ....
> }
>
> auto experimentalReplacement(string parameter,VaraidcParams ...)() {
>  // do the same thing very fast and dangerous
> }
>
> is the following
>
> auto veryStableAPI(bool brave=false, string parameter,VaraiadicParams...) {
>  static if (!brave)
>      // do something very slow and stable;
>  else
>      // do the same thing very fast and dangerous
> }
> valid according to spec ?

import std.stdio;
import core.vararg;

auto veryStableAPI(bool brave = false)(string parameter, ...)
{
	static if (!brave)
	{
		pragma(msg, "I'm not brave");
	}
	else
	{
		pragma(msg, "I'm very brave");
	}
}

void main(string[] args)
{
	veryStableAPI("test");
	veryStableAPI!(true)("test");
}

> import std.stdio;
> import core.vararg;
>
> auto veryStableAPI(bool brave = false)(string parameter, ...)
> {
> 	static if (!brave)
> 	{
> 		pragma(msg, "I'm not brave");
> 	}
> 	else
> 	{
> 		pragma(msg, "I'm very brave");
> 	}
> }
>
> void main(string[] args)
> {
> 	veryStableAPI("test");
> 	veryStableAPI!(true)("test");
> }

Sorry but that does not anwer my question.
is it legal or is it not ?

> valid according to spec ?

Only trailing parameter can have default arguments.

On Wednesday, 29 January 2014 at 18:24:22 UTC, Uplink_Coder wrote:
> is it legal or is it not ?

Yours isn't, no.