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Why (v1<<8 + v2) different from (v1<<8 | v2)?
May 25, 2022
step8
May 25, 2022
Paul Backus
May 25, 2022
step8
May 25, 2022
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step8
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I run following test code:
  int v1 = 22;
  int v2 = 23;
  writeln( v1<<8 + v2 );		
  writeln( v1<<8 | v2 );

result is 0 and 5655
Why ( v1<<8 + v2 ) = 0 ?

May 25, 2022
Gravatar of Paul BackusPosted by Paul Backus
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Paul Backus
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On Wednesday, 25 May 2022 at 12:42:04 UTC, step8 wrote:

> 
I run following test code:
  int v1 = 22;
  int v2 = 23;
  writeln( v1<<8 + v2 );		
  writeln( v1<<8 | v2 );

result is 0 and 5655
Why ( v1<<8 + v2 ) = 0 ?

+ has a higher precedence than <<, so the first line is actually v1 << (8 + v2).

May 25, 2022
Gravatar of step8Posted by step8
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Thanks:)
writeln( (v1<<8) + v2 ); is ok
On Wednesday, 25 May 2022 at 12:51:07 UTC, Paul Backus wrote:

>

On Wednesday, 25 May 2022 at 12:42:04 UTC, step8 wrote:

> 
I run following test code:
  int v1 = 22;
  int v2 = 23;
  writeln( v1<<8 + v2 );		
  writeln( v1<<8 | v2 );

result is 0 and 5655
Why ( v1<<8 + v2 ) = 0 ?

+ has a higher precedence than <<, so the first line is actually v1 << (8 + v2).

(