I want to split a string using multiple separators. In std.array the split function has a version where it takes a range as a separator, but it works differently than what I want. Say if I call it with " -> " it will search for the whole thing together. I want to pass split a list of separators say [":", ",", ";"] and if it finds any of those to split it.

Sorry if this questions is stupid but I cant find how to do it.

On Wednesday, 16 December 2015 at 14:18:28 UTC, Borislav Kosharov wrote:
> I want to split a string using multiple separators. In std.array the split function has a version where it takes a range as a separator, but it works differently than what I want. Say if I call it with " -> " it will search for the whole thing together. I want to pass split a list of separators say [":", ",", ";"] and if it finds any of those to split it.
>
> Sorry if this questions is stupid but I cant find how to do it.


void main()
{

   import std.stdio: writeln;
   writeln("abc,def;ghi".splitter!(a => !":,;".find(a).empty).array);
}

On Wednesday, 16 December 2015 at 14:47:26 UTC, Dragos Carp wrote:
> On Wednesday, 16 December 2015 at 14:18:28 UTC, Borislav Kosharov wrote:
>> I want to split a string using multiple separators. In std.array the split function has a version where it takes a range as a separator, but it works differently than what I want. Say if I call it with " -> " it will search for the whole thing together. I want to pass split a list of separators say [":", ",", ";"] and if it finds any of those to split it.
>>
>> Sorry if this questions is stupid but I cant find how to do it.
>
>
> void main()
> {
>
>    import std.stdio: writeln;
>    writeln("abc,def;ghi".splitter!(a => !":,;".find(a).empty).array);
> }

The call to `array` is unnecessary in this example, and you can use the shorter `canFind`:

   writeln("abc,def;ghi".splitter!(a => ":,;".canFind(a)));

On Wednesday, 16 December 2015 at 15:27:22 UTC, Marc Schütz wrote:
> On Wednesday, 16 December 2015 at 14:47:26 UTC, Dragos Carp wrote:
>> On Wednesday, 16 December 2015 at 14:18:28 UTC, Borislav Kosharov wrote:
>>> I want to split a string using multiple separators. In std.array the split function has a version where it takes a range as a separator, but it works differently than what I want. Say if I call it with " -> " it will search for the whole thing together. I want to pass split a list of separators say [":", ",", ";"] and if it finds any of those to split it.
>>>
>>> Sorry if this questions is stupid but I cant find how to do it.
>>
>>
>> void main()
>> {
>>
>>    import std.stdio: writeln;
>>    writeln("abc,def;ghi".splitter!(a => !":,;".find(a).empty).array);
>> }
>
> The call to `array` is unnecessary in this example, and you can use the shorter `canFind`:
>
>    writeln("abc,def;ghi".splitter!(a => ":,;".canFind(a)));


Dear Borislav, Dragos and Marc,

Thanks for this question (@Borislav) and the solution's approaches (@Dragos and @Marc). Today, I had the same task and tried to find a solution for it. Unfortunately, the proposed solutions seem not work.

Here is the version from Dragos (run it directly on the web):
http://ideone.com/fglk0s

Here the version from Marc:
http://ideone.com/yCaYrD

In both cases, I got the "Error: template std.algorithm.iteration.splitter cannot deduce function from argument types [...]" message.

Can anyone help me with a functional example? That would be great :)


Best regards,
Thorsten

On 5/12/16 3:25 PM, Thorsten Sommer wrote:
> On Wednesday, 16 December 2015 at 15:27:22 UTC, Marc Schütz wrote:
>> On Wednesday, 16 December 2015 at 14:47:26 UTC, Dragos Carp wrote:
>>> On Wednesday, 16 December 2015 at 14:18:28 UTC, Borislav Kosharov wrote:
>>>> I want to split a string using multiple separators. In std.array the
>>>> split function has a version where it takes a range as a separator,
>>>> but it works differently than what I want. Say if I call it with "
>>>> -> " it will search for the whole thing together. I want to pass
>>>> split a list of separators say [":", ",", ";"] and if it finds any
>>>> of those to split it.
>>>>
>>>> Sorry if this questions is stupid but I cant find how to do it.
>>>
>>>
>>> void main()
>>> {
>>>
>>>    import std.stdio: writeln;
>>>    writeln("abc,def;ghi".splitter!(a => !":,;".find(a).empty).array);
>>> }
>>
>> The call to `array` is unnecessary in this example, and you can use
>> the shorter `canFind`:
>>
>>    writeln("abc,def;ghi".splitter!(a => ":,;".canFind(a)));
>
>
> Dear Borislav, Dragos and Marc,
>
> Thanks for this question (@Borislav) and the solution's approaches
> (@Dragos and @Marc). Today, I had the same task and tried to find a
> solution for it. Unfortunately, the proposed solutions seem not work.
>
> Here is the version from Dragos (run it directly on the web):
> http://ideone.com/fglk0s
>
> Here the version from Marc:
> http://ideone.com/yCaYrD
>
> In both cases, I got the "Error: template
> std.algorithm.iteration.splitter cannot deduce function from argument
> types [...]" message.
>
> Can anyone help me with a functional example? That would be great :)

You are missing some imported symbols.

Unfortunately, due to the way binaryFun works, this masks the true error (can't compile your lambda!).

https://dpaste.dzfl.pl/79399404f2ad

Note, the ideone compiler is very out of date. But it probably would work with the correct imports.

-Steve

Wow, thanks Steve :)

On Wednesday, 16 December 2015 at 15:27:22 UTC, Marc Schütz wrote:
> On Wednesday, 16 December 2015 at 14:47:26 UTC, Dragos Carp wrote:
>> On Wednesday, 16 December 2015 at 14:18:28 UTC, Borislav Kosharov wrote:
>>> I want to split a string using multiple separators. In std.array the split function has a version where it takes a range as a separator, but it works differently than what I want. Say if I call it with " -> " it will search for the whole thing together. I want to pass split a list of separators say [":", ",", ";"] and if it finds any of those to split it.
>>>
>>> Sorry if this questions is stupid but I cant find how to do it.
>>
>>
>> void main()
>> {
>>
>>    import std.stdio: writeln;
>>    writeln("abc,def;ghi".splitter!(a => !":,;".find(a).empty).array);
>> }
>
> The call to `array` is unnecessary in this example, and you can use the shorter `canFind`:
>
>    writeln("abc,def;ghi".splitter!(a => ":,;".canFind(a)));

What about "abc,;;.. def" you get empty strings?

I've come up with this:

import std.stdio : writeln;
import std.algorithm : canFind, splitter, filter;

void main() {
	writeln("abc,:def;ghi". // or "abc, def. Ghi"
		splitter!(a => " .,:;".canFind(a)).
		filter!(a => a.length));
}