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| Posted by Andrey Zherikov in reply to Imperatorn | PermalinkReply |
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Andrey Zherikov
Posted in reply to Imperatorn
| On Saturday, 30 October 2021 at 00:52:23 UTC, Imperatorn wrote:
> On Saturday, 30 October 2021 at 00:49:04 UTC, Stanislav Blinov wrote:
> On Friday, 29 October 2021 at 21:00:48 UTC, Steven Schveighoffer wrote:
> This is incorrect, the buckets are each heap allocated. Just the array of bucket pointers would change.
In addition, AAs do not deallocate the key/value pairs ever. You are safe to obtain a pointer to a value and it will stay there, even if you remove the key.
Who's going to document these implementation details? ;) I mean, if no one, then the above shouldn't be stated. Wouldn't you agree?
Given the premise of the question at hand, it does seem useful to know these. But at least one should stress what is and isn't subject to change (even if unlikely).
This should be documented for sure
I did small test and it printed the same values three times so even rehash doesn't change the address of the value:
long[long] aa = [0:0];
writeln(&aa[0]);
foreach(i; 0 .. 100_000_000)
aa[i]=i;
writeln(&aa[0]);
aa.rehash;
writeln(&aa[0]);
So it seems pretty safe to store a pointer to a value in AA. And I agree that this should definitely be documented.
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