October 24, 2016 Re: [OT] fastest fibbonacci | ||||
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Posted in reply to Stefam Koch | On Sunday, 23 October 2016 at 23:17:28 UTC, Stefam Koch wrote:
> On Sunday, 23 October 2016 at 19:59:16 UTC, Minas Mina wrote:
>> On Sunday, 23 October 2016 at 13:04:30 UTC, Stefam Koch wrote:
>>> Hi Guys,
>>>
>>> while brushing up on my C and algorithm skills, accidently created a version of fibbonaci which I deem to be faster then the other ones floating around.
>>>
>>> It's also more concise
>>>
>>> the code is :
>>>
>>> int computeFib(int n)
>>> {
>>> int t = 1;
>>> int result = 0;
>>>
>>> while(n--)
>>> {
>>> result = t - result;
>>> t = t + result;
>>> }
>>>
>>> return result;
>>> }
>>
>> You can even calculate Fibonacci in O(1).
>
> An approximation of it.
The fibonacci sequence can be represented exactly as a linear combination of two exponential functions, but the two bases of the exponentials and the linear multipliers of them are irrational numbers, which cannot be represented exactly on a computer.
However the rounding error is so small, that rounding to int will give you always the correct answer as long as you stay within the precision limit of the floating point type you use, e.g. a real should give you 64-bit fibonacci in O(1), if the exponential function is O(1).
PS: the exact formula is fib(n) = 1/sqrt(5) * (0.5 + 0.5sqrt(5))^n - 1/sqrt(5) * (0.5 - 0.5sqrt(5))^n. If you round to integer anyway, the second term can be ignored as it is always <= 0.5.
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October 24, 2016 Re: [OT] fastest fibbonacci | ||||
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Posted in reply to Matthias Bentrup | On Monday, 24 October 2016 at 08:20:26 UTC, Matthias Bentrup wrote:
> PS: the exact formula is fib(n) = 1/sqrt(5) * (0.5 + 0.5sqrt(5))^n - 1/sqrt(5) * (0.5 - 0.5sqrt(5))^n. If you round to integer anyway, the second term can be ignored as it is always <= 0.5.
You can simply write it as:
round(phi^n/sqrt(5));
Check my example above :)
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October 24, 2016 Re: [OT] fastest fibbonacci | ||||
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Posted in reply to Andrea Fontana | On Monday, 24 October 2016 at 08:54:38 UTC, Andrea Fontana wrote:
> You can simply write it as:
> round(phi^n/sqrt(5));
>
> Check my example above :)
Ran your example and it's perfect for 32bit code. But 64bit, not so much. It's only good through 71 iterations (longs) then it starts having errors. Also for some odd reason the input is one off, so i had to add a -1 to the input for it to align. This makes it accurate to 41/64 bit results.
for(int i = 1; i < 100; ++i) {
auto cf = computeFib(i);
auto cfm = computeFibMagic(i-1); //with magic numbers exampled
writeln(i, ": ", cf, "\t", cfm, "\t", cf == cfm);
}
64: 10610209857723 10610209857723 true
65: 17167680177565 17167680177565 true
66: 27777890035288 27777890035288 true
67: 44945570212853 44945570212853 true
68: 72723460248141 72723460248141 true
69: 117669030460994 117669030460994 true
70: 190392490709135 190392490709135 true
71: 308061521170129 308061521170129 true
72: 498454011879264 498454011879265 false
73: 806515533049393 806515533049395 false
74: 1304969544928657 1304969544928660 false
75: 2111485077978050 2111485077978055 false
76: 3416454622906707 3416454622906715 false
77: 5527939700884757 5527939700884771 false
78: 8944394323791464 8944394323791487 false
79: 14472334024676221 14472334024676258 false
80: 23416728348467685 23416728348467746 false
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October 25, 2016 Re: [OT] fastest fibbonacci | ||||
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Posted in reply to Era Scarecrow | On Monday, 24 October 2016 at 19:03:51 UTC, Era Scarecrow wrote:
> It's only good through 71 iterations (longs) then it starts having errors. Also for some odd reason the input is one off, so I had to add a -1 to the input for it to align. This makes it accurate to 41/64 bit results.
>
> 71: 308061521170129 308061521170129 true
> 72: 498454011879264 498454011879265 false
Hmm as an experiment I changed from doubles to reals, and got a slightly higher result, up to 85 giving us a 58/64
83: 99194853094755497 99194853094755497 true
84: 160500643816367088 160500643816367088 true
85: 259695496911122585 259695496911122585 true
86: 420196140727489673 420196140727489674 false
87: 679891637638612258 679891637638612259 false
88: 1100087778366101931 1100087778366101933 false
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October 25, 2016 Re: [OT] fastest fibbonacci | ||||
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Posted in reply to Era Scarecrow | On Tuesday, 25 October 2016 at 07:05:20 UTC, Era Scarecrow wrote:
> Hmm as an experiment I changed from doubles to reals, and got a slightly higher result, up to 85 giving us a 58/64
Of course floating precision is not unlimited :)
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