On 7/9/21 12:21 AM, rempas wrote:

>    while (prompt[i] != '{' && i < len) {

In addition to what others said, you can take advantage of ranges to separate concerns of filtering and iteration. Here are two ways:

import core.stdc.stdio;
import std.algorithm;

// Same as your original
void print(T)(string prompt, T args...) {
  prompt
    .filter!(c => c != '{')
    .each!(c => printf("%c", c));

  // If you are not familiar with the shorthand lambda syntax,
  // I read c => foo(c) as "given c, produce foo(c)."
  //
  // Well... 'each' is different because it does not
  // produce anything. It its case: "given c, do this."
}

// This one dispatches filtering to another function but
// still uses a 'foreach' loop
void print2(T)(string prompt, T args...) {
  foreach (c; prompt.sansCurly) {
    printf("%c", c);
  }
}

// I used R instead of 'string' in case it will be more useful
auto sansCurly(R)(R range) {
  return range.filter!(c => c != '{');
}

void main() {
  print("Hello, {world!\n", 10);
  print2("Hello, {world!\n", 10);
}

Ali

On Friday, 9 July 2021 at 11:56:40 UTC, Ali Çehreli wrote:
> In addition to what others said, you can take advantage of ranges to separate concerns of filtering and iteration. Here are two ways:
>
> [...]

Of course another help from the legend himself ;) As always thanks a lot and have an amazing day!