How to call a function from a dll created with d ?

module dimedll;
import core.sys.windows.windows;
import core.sys.windows.dll; // I don't what is this for.
import std.stdio;


mixin SimpleDllMain;

export void testFunc() {
    writeln("This is from dll");
}

So now I have a dll fie named dimedll.dll and a lib file named dimedll.lib.
Now, I have created a d source file called dime.d and wrote this code.

import std.stdio;
import core.sys.windows.windows;
import std.stdio : log = writeln;

pragma(lib, "dimedll.lib");

extern void testFunc();

void main() { 	
	log("Lets build our own ime");
	testFunc();		
}

Everything seems to be okay. So I called dmd with this command.
dmd -i -run dime.d
But I got this error message.

dime.obj : error LNK2019: unresolved external symbol __D4dime8testFuncFZv referenced in function __Dmain
dime.exe : fatal error LNK1120: 1 unresolved externals
Error: linker exited with status 1120```
How to fix this ?

On Friday, 1 July 2022 at 22:32:24 UTC, Vinod K Chandran wrote: > So using a `def` file is a must I think. no it is not. you just need to mark things export and make sure names match (including module name)

On Friday, 1 July 2022 at 22:38:17 UTC, Adam D Ruppe wrote: > On Friday, 1 July 2022 at 22:32:24 UTC, Vinod K Chandran wrote: >> So using a `def` file is a must I think. > > no it is not. you just need to mark things export and make sure names match (including module name) Thanks for the reply. These are my questions. 1. `mixin` statement in dll file - Do I need to export it ? 2. There is only one function and that is marked with `export`. 3. Name of the module which I wrote the dll code is `dimedll`. So my dll file's name is `dimedll.dll`. And my lib file's name is `dimedll.lib`. No change in names. 4. Name of my exported function is `testFunc`. And the same name is used in `extern` keyword and the calling site. So where do I check again ?

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