Hello I am trying to convert BigInt to string like that while trying to sort it:

string s1 = to!string(a).dup.sort;

and get an error

cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string

what do I do wrong?

On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
> Hello I am trying to convert BigInt to string like that while trying to sort it:
>
> string s1 = to!string(a).dup.sort;
>
> and get an error
>
> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>
> what do I do wrong?

try

".idup"

otherwise

"auto s1 = "

On Thursday, 5 November 2015 at 16:35:01 UTC, BBasile wrote:
> On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
>> Hello I am trying to convert BigInt to string like that while trying to sort it:
>>
>> string s1 = to!string(a).dup.sort;
>>
>> and get an error
>>
>> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>>
>> what do I do wrong?
>
> try
>
> ".idup"
>
> otherwise
>
> "auto s1 = "

auto did it, but idup leads to

Error: can only sort a mutable array

On Thursday, 5 November 2015 at 16:39:03 UTC, Namal wrote:
> On Thursday, 5 November 2015 at 16:35:01 UTC, BBasile wrote:
>> On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
>>> Hello I am trying to convert BigInt to string like that while trying to sort it:
>>>
>>> string s1 = to!string(a).dup.sort;
>>>
>>> and get an error
>>>
>>> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>>>
>>> what do I do wrong?
>>
>> try
>>
>> ".idup"
>>
>> otherwise
>>
>> "auto s1 = "
>
> auto did it, but idup leads to
>
> Error: can only sort a mutable array

sorry, I feel embarrassed now...good luck i wish you.

On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
> Hello I am trying to convert BigInt to string like that while trying to sort it:
>
> string s1 = to!string(a).dup.sort;
>
> and get an error
>
> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>
> what do I do wrong?

Try this instead:

string s1 = to!string(a).idup.sort()

I suspect there are two things happening here. First, calling dup on a string yields char[], not string (the difference being that string is immutable and char[] is not). A char[] cannot implicitly convert to string due to the difference in immutability, although the compiler *should* realize that the result of dup is a "unique" expression and be able to implicitly convert it... It may be because you then pass it to sort, which must keep it as a char[].

The second issue is that using .sort instead of .sort() (note the parentheses) calls the built-in sort instead of std.algorithm.sort, which is strongly discouraged. You should always use std.algorithm.sort over the built-in sort, which you can do just by appending those parentheses.

On Thursday, 5 November 2015 at 16:45:10 UTC, Meta wrote:
> On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
>> Hello I am trying to convert BigInt to string like that while trying to sort it:
>>
>> string s1 = to!string(a).dup.sort;
>>
>> and get an error
>>
>> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>>
>> what do I do wrong?
>
> Try this instead:
>
> string s1 = to!string(a).idup.sort()
>
If I try it like that i get:

Error: template std.algorithm.sorting.sort cannot deduce function from argument types !()(char[]), candidates are:

/../src/phobos/std/algorithm/sorting.d(996):

On Thursday, 5 November 2015 at 16:53:50 UTC, Namal wrote:
> On Thursday, 5 November 2015 at 16:45:10 UTC, Meta wrote:
>> On Thursday, 5 November 2015 at 16:29:30 UTC, Namal wrote:
>>> Hello I am trying to convert BigInt to string like that while trying to sort it:
>>>
>>> string s1 = to!string(a).dup.sort;
>>>
>>> and get an error
>>>
>>> cannot implicitly convert expression (_adSortChar(dup(to(a)))) of type char[] to string
>>>
>>> what do I do wrong?
>>
>> Try this instead:
>>
>> string s1 = to!string(a).idup.sort()
>>
> If I try it like that i get:
>
> Error: template std.algorithm.sorting.sort cannot deduce function from argument types !()(char[]), candidates are:
>
> /../src/phobos/std/algorithm/sorting.d(996):

string s1 = to!string(a).dup.sort.idup;

On Thursday, 5 November 2015 at 17:13:07 UTC, Ilya Yaroshenko wrote:

> string s1 = to!string(a).dup.sort.idup;
well, but I was just told not to use sort ??

Namal:

> Hello I am trying to convert BigInt to string like that while trying to sort it:

void main() {
    import std.stdio, std.algorithm, std.conv, std.bigint, std.string;

    auto n = 17.BigInt ^^ 179;
    n.text.dup.representation.sort().release.assumeUTF.writeln;
}

Bye,
bearophile

> void main() {
>     import std.stdio, std.algorithm, std.conv, std.bigint, std.string;
>
>     auto n = 17.BigInt ^^ 179;
>     n.text.dup.representation.sort().release.assumeUTF.writeln;
> }

Better:

    n.to!(char[]).representation.sort().release.assumeUTF.writeln;

Bye,
bearophile