quick question: What is the most efficient way to covert a string to a char array?

On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
> quick question: What is the most efficient way to covert a string to a char array?

string s = "str";
char[] strArr = s.dup;

On Tuesday, 2 June 2015 at 15:26:50 UTC, Dennis Ritchie wrote:
> On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
>> quick question: What is the most efficient way to covert a string to a char array?
>
> string s = "str";
> char[] strArr = s.dup;

Thanks! :)

On Tuesday, 2 June 2015 at 15:32:12 UTC, Kyoji Klyden wrote:
> On Tuesday, 2 June 2015 at 15:26:50 UTC, Dennis Ritchie wrote:
>> On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
>>> quick question: What is the most efficient way to covert a string to a char array?
>>
>> string s = "str";
>> char[] strArr = s.dup;
>
> Thanks! :)

Note that this will allocate a new garbage collected array.

On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
> quick question: What is the most efficient way to covert a string to a char array?

A string is, by definition in D, a character array, specifically `immutable(char)[]`. It's not like, for example, Java in which it's a completely separate type; you can perform all the standard array operations on strings.

If you need to mutate a string, then you can create a mutable `char[]` by doing `somestring.dup` as Dennis already mentioned.

On Tuesday, 2 June 2015 at 15:53:33 UTC, Alex Parrill wrote:
> A string is, by definition in D, a character array, specifically `immutable(char)[]`. It's not like, for example, Java in which it's a completely separate type; you can perform all the standard array operations on strings.

Yes, I believe that this is a problem in D, and because when you create a multidimensional array mutable strings having real troubles with .deepDup. I think that will solve the problem of a new string data type is a built-in D, and because writing .dup, to create a mutated string, - it's really funny! This is problem!

On Tuesday, 2 June 2015 at 15:53:33 UTC, Alex Parrill wrote:
> On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
>> quick question: What is the most efficient way to covert a string to a char array?
>
> A string is, by definition in D, a character array, specifically `immutable(char)[]`. It's not like, for example, Java in which it's a completely separate type; you can perform all the standard array operations on strings.
>
> If you need to mutate a string, then you can create a mutable `char[]` by doing `somestring.dup` as Dennis already mentioned.

The problem I was having was actually that an opengl function (specifically glShaderSource) wouldn't accept strings. I'm still can't get it to work actually :P

glShaderSource (uint, int, const(char*)*, const(int)*)

This one function is a bugger, been going at this for hours.


On Tuesday, 2 June 2015 at 15:38:24 UTC, Meta wrote:
>
> Note that this will allocate a new garbage collected array.

Thx for the heads up

On Tuesday, 2 June 2015 at 16:23:26 UTC, Kyoji Klyden wrote:
> On Tuesday, 2 June 2015 at 15:53:33 UTC, Alex Parrill wrote:
>> On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
>>> quick question: What is the most efficient way to covert a string to a char array?
>>
>> A string is, by definition in D, a character array, specifically `immutable(char)[]`. It's not like, for example, Java in which it's a completely separate type; you can perform all the standard array operations on strings.
>>
>> If you need to mutate a string, then you can create a mutable `char[]` by doing `somestring.dup` as Dennis already mentioned.
>
> The problem I was having was actually that an opengl function (specifically glShaderSource) wouldn't accept strings. I'm still can't get it to work actually :P
>
> glShaderSource (uint, int, const(char*)*, const(int)*)
>
> This one function is a bugger, been going at this for hours.
>
>
> On Tuesday, 2 June 2015 at 15:38:24 UTC, Meta wrote:
>>
>> Note that this will allocate a new garbage collected array.
>
> Thx for the heads up

glShaderSource accepts an array of null-terminated strings. Try this:


	import std.string : toStringz;

	string sources = source.toStringz;
	int len = source.length;

	glShaderSource(id, sources, 1, &sources, &len);

On Tuesday, 2 June 2015 at 16:26:30 UTC, Alex Parrill wrote:
> On Tuesday, 2 June 2015 at 16:23:26 UTC, Kyoji Klyden wrote:
>> On Tuesday, 2 June 2015 at 15:53:33 UTC, Alex Parrill wrote:
>>> On Tuesday, 2 June 2015 at 15:07:58 UTC, Kyoji Klyden wrote:
>>>> quick question: What is the most efficient way to covert a string to a char array?
>>>
>>> A string is, by definition in D, a character array, specifically `immutable(char)[]`. It's not like, for example, Java in which it's a completely separate type; you can perform all the standard array operations on strings.
>>>
>>> If you need to mutate a string, then you can create a mutable `char[]` by doing `somestring.dup` as Dennis already mentioned.
>>
>> The problem I was having was actually that an opengl function (specifically glShaderSource) wouldn't accept strings. I'm still can't get it to work actually :P
>>
>> glShaderSource (uint, int, const(char*)*, const(int)*)
>>
>> This one function is a bugger, been going at this for hours.
>>
>>
>> On Tuesday, 2 June 2015 at 15:38:24 UTC, Meta wrote:
>>>
>>> Note that this will allocate a new garbage collected array.
>>
>> Thx for the heads up
>
> glShaderSource accepts an array of null-terminated strings. Try this:
>
>
> 	import std.string : toStringz;
>
> 	string sources = source.toStringz;
> 	int len = source.length;
>
> 	glShaderSource(id, sources, 1, &sources, &len);

src:

        string source = readText("test.glvert");
	
	const string sources = source.toStringz;
	const int len = source.length;
	
	GLuint vertShader = glCreateShader( GL_VERTEX_SHADER );
	
	glShaderSource(vertShader, 1, &sources, &len);

pt.d(26): Error: cannot implicitly convert expression (toStringz(source)) of type immutable(char)* to const(string)

pt.d(34): Error: function pointer glShaderSource (uint, int, const(char*)*, const(int)*) is not callable using argument types (uint, int, const(string)*, const(int)*)

-

I also tried passing the char array instead but no go.. What am I missing? :\

On Tuesday, 2 June 2015 at 16:41:38 UTC, Kyoji Klyden wrote:

> src:
>
>         string source = readText("test.glvert");
> 	
> 	const string sources = source.toStringz;
> 	const int len = source.length;
> 	
> 	GLuint vertShader = glCreateShader( GL_VERTEX_SHADER );
> 	
> 	glShaderSource(vertShader, 1, &sources, &len);
>
> pt.d(26): Error: cannot implicitly convert expression (toStringz(source)) of type immutable(char)* to const(string)
>
> pt.d(34): Error: function pointer glShaderSource (uint, int, const(char*)*, const(int)*) is not callable using argument types (uint, int, const(string)*, const(int)*)
>
> -
>
> I also tried passing the char array instead but no go.. What am I missing? :\

Oops, do `const immutable(char)* sources = source.toStringz` (or just use `auto sources = ...`).