Thread overview
Why 2 ^^ 1 ^^ 2 = 2?
Oct 22, 2017
Ilya Yaroshenko
Oct 22, 2017
Timon Gehr
Oct 22, 2017
kinbelle
Oct 22, 2017
Ivan Kazmenko
Oct 26, 2017
Kagamin
Oct 26, 2017
Kagamin
Oct 28, 2017
Ivan Kazmenko
Nov 01, 2017
Q. Schroll
Nov 01, 2017
Igor Shirkalin
October 22, 2017
.. i thought it should be (2 ^^ 1) ^^ 2 = 4
October 22, 2017
On 22.10.2017 16:20, Ilya Yaroshenko wrote:
> .. i thought it should be (2 ^^ 1) ^^ 2 = 4

2 ^^ (1 ^^ 2) == 2

It is standard for ^/**/^^ to be right-associative. (This is also the standard convention in mathematics.)
October 22, 2017
On Sunday, 22 October 2017 at 14:44:04 UTC, Timon Gehr wrote:
> On 22.10.2017 16:20, Ilya Yaroshenko wrote:
>> .. i thought it should be (2 ^^ 1) ^^ 2 = 4
>
> 2 ^^ (1 ^^ 2) == 2
>
> It is standard for ^/**/^^ to be right-associative. (This is also the standard convention in mathematics.)

true
October 22, 2017
On Sunday, 22 October 2017 at 14:44:04 UTC, Timon Gehr wrote:
> On 22.10.2017 16:20, Ilya Yaroshenko wrote:
>> .. i thought it should be (2 ^^ 1) ^^ 2 = 4
>
> 2 ^^ (1 ^^ 2) == 2
>
> It is standard for ^/**/^^ to be right-associative. (This is also the standard convention in mathematics.)

Yeah, and a height-3 tower $a^{b^c}$ (TEX notation) actually means "a to the power of (b to the power of c)", not the other way around.  Otherwise, it can be written as $a^{b \cdot c}$, which is only a height-2 tower.

The convention also makes at least the following sense.  An expression like
(((a ^^ b) ^^ c) ^^ d) ^^ e
already has an almost bracket-free notation as
a ^^ (b * c * d * e).
So it is useful to have a bracket-free way to write the other-way-associative variant,
a ^^ (b ^^ (c ^^ (d ^^ e))).

Ivan Kazmenko.

October 26, 2017
On Sunday, 22 October 2017 at 22:28:48 UTC, Ivan Kazmenko wrote:
> Yeah, and a height-3 tower $a^{b^c}$ (TEX notation) actually means "a to the power of (b to the power of c)", not the other way around.

Because you have explicit braces there.

Math doesn't have precedence for exponentiation operator because it's written as a superscript, which is always unambiguous.
October 26, 2017
On Sunday, 22 October 2017 at 22:28:48 UTC, Ivan Kazmenko wrote:
> Yeah, and a height-3 tower $a^{b^c}$ (TEX notation)

Is $a^{b^c}$ the same as ${a^b}^c$ ? They are drawn slightly differently, so I suppose it's ambiguous indeed.
October 28, 2017
On Thursday, 26 October 2017 at 10:02:54 UTC, Kagamin wrote:
> On Sunday, 22 October 2017 at 22:28:48 UTC, Ivan Kazmenko wrote:
>> Yeah, and a height-3 tower $a^{b^c}$ (TEX notation)
>
> Is $a^{b^c}$ the same as ${a^b}^c$ ? They are drawn slightly differently, so I suppose it's ambiguous indeed.

Surely not the same.

"3 to the power of (3 to the power of 3)" is "3 to the power of 27", or 7,625,597,484,987.
"(3 to the power of 3) to the power of 3" is "27 to the power of 3", or 2187.

For an argument, the TEX command "^" accepts either a single character or a bracket-enclosed string of arbitrary length.  So $3^3^3$ indeed transforms to ${3^3}^3$, but not for some deeper reason this time.

Ivan Kazmenko.

November 01, 2017
On Saturday, 28 October 2017 at 00:14:15 UTC, Ivan Kazmenko wrote:
> For an argument, the TEX command "^" accepts either a single character or a bracket-enclosed string of arbitrary length.  So $3^3^3$ indeed transforms to ${3^3}^3$, but not for some deeper reason this time.

On my TeX compiler, $3^3^3$ makes it give a warning/error.

November 01, 2017
On Sunday, 22 October 2017 at 14:20:20 UTC, Ilya Yaroshenko wrote:
> .. i thought it should be (2 ^^ 1) ^^ 2 = 4

Imagine 2^^10^^10^^7. It's a big number, isn't? (up-up-and up) Where would you start from?