On Thursday, 2 January 2014 at 15:31:25 UTC, bearophile wrote:
> Gary Willoughby:
>
>> Another question: how do i convert const(char)** to string[]?
>
> If you know that you have N strings, then a solution is (untested):
>
> pp[0 .. N].map!text.array
>
> If it doesn't work, try:
>
> pp[0 .. N].map!(to!string).array
>
> Bye,
> bearophile

Thanks, both work well:

I've noticed that const(char)** can be accessed via indexes:

writefln("%s", pp[0].to!(string)); //etc.

cool!

Gary Willoughby:

> I've noticed that const(char)** can be accessed via indexes:
>
> writefln("%s", pp[0].to!(string)); //etc.
>
> cool!

This is a feature that works with all pointers to a sequence of items, like in C. But array bounds are not verified, so it's more bug-prone. So if you know the length it's better to slice the pointer as soon as possible, and then use the slice:

auto ap = pp[0 .. N];
writefln("%s", ap[0].text);

Or just:

printf("%s\n", ap[0]);

Bye,
bearophile