June 07, 2002 Problem with File streams | ||||
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I have tried both the original stream.d and the one availible at DedicateD and have come to the same problem both times. I use the following code to open a file. It is some c++ code from Uni I am trying to convert over. The text files mentioned are "\n" delimited lists of words. import stream; alias char[] string; void main( char[][] args ) { string myFile, yourFile; myFile = "lista.txt"; yourFile = "listb.txt"; printf("Got through the declarations, woowoo\n\n\n"); string[] myList, yourList; campItems ( myFile, myList ); campItems ( yourFile, yourList ); for ( int i = 0; i < myList.length; i++ ) { printf ( "'%.*s' ", myList[i] ); } for ( int i = 0; i < yourList.length; i++ ) { printf ( "'%.*s' ", yourList[i] ); } /* Have to concatenate the 2 Lists, implement the unique( string[] inList ) function and then display the lists to the screen */ } void campItems ( string inFile, inout string[] inList ) { printf("I am in the function now\n\n"); File tempFile; tempFile.open(inFile); printf("After file declaration and opening"); while ( !tempFile.eof() ) { inList[inList.length - 1] = tempFile.readLine(); } } It never reaches the line: printf("After file declaration and opening"); Bot only that but it send the computer into a major memory leak ie. used up all 512mB of physical memory and then 1.3gB of virtual ram before I caught it. Something is severly stuffed big time here, is it just me or has anyone else has similar problems! Argh! |
June 07, 2002 Re: Problem with File streams | ||||
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Posted in reply to Ryan Michel | "Ryan Michel" <ryan@michel.com.au> wrote in message news:1103_1023439083@news.digitalmars.com... > File tempFile; > tempFile.open(inFile); Err... and where is "tempFile = new File" ??? |
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