January 17, 2003 type checking problem? | ||||
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The following yields incorrect result when characters are inputed instead of integers. import stream; int main() { const int answer = 10; int guess; printf("Pick a number: "); scanf("%d", &guess); if(answer == guess) { printf("Answer = %d.", guess); } else if(answer > guess) { printf("Answer > guess."); } else if(answer < guess) { printf("Answer < guess."); } else { printf("That wasn't a number."); } return 0; } |
January 17, 2003 Re: type checking problem? | ||||
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Posted in reply to Andrew Edwards | If you change "guess" to a float, I think it works as expected. Apparently, integers default to 0 when a non-number is given. Try this:
import stream;
int main()
{
const int answer = 10;
float guess;
printf("Pick a number: ");
scanf("%f", &guess);
if(answer == guess)
{
printf("Answer = %f.", guess);
}
else if(answer > guess)
{
printf("Answer > guess.");
}
else if(answer < guess)
{
printf("Answer < guess.");
}
else
{
printf("That wasn't a number.");
}
return 0;
}
Andrew Edwards wrote:
> The following yields incorrect result when characters are inputed instead of
> integers.
>
> import stream;
>
> int main()
> {
> const int answer = 10;
> int guess;
>
> printf("Pick a number: ");
> scanf("%d", &guess);
>
> if(answer == guess)
> {
> printf("Answer = %d.", guess);
> }
> else if(answer > guess)
> {
> printf("Answer > guess.");
> }
> else if(answer < guess)
> {
> printf("Answer < guess.");
> }
> else
> {
> printf("That wasn't a number.");
> }
>
> return 0;
> }
>
>
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