September 18, 2007
http://d.puremagic.com/issues/show_bug.cgi?id=1515

           Summary: compiler accepts invalid template declaration
           Product: D
           Version: 1.014
          Platform: PC
        OS/Version: Windows
            Status: NEW
          Severity: trivial
          Priority: P2
         Component: DMD
        AssignedTo: bugzilla@digitalmars.com
        ReportedBy: davidl@126.com


template A(T)
{
        alias T type;
}
template B(T:A!(T).type)    // I think compiler should ban the use of reuse the
same type identifier in the specialization part.
{
}
//mixin B!(int);  // even though you can't instantiate the template, the
compiler can actually emit nicer message;


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October 29, 2007
http://d.puremagic.com/issues/show_bug.cgi?id=1515


smjg@iname.com changed:

           What    |Removed                     |Added
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                 CC|                            |smjg@iname.com




------- Comment #1 from smjg@iname.com  2007-10-29 07:52 -------
AIUI this is by design, though admittedly it's a rather strange design.

http://www.digitalmars.com/d/1.0/template.html

template TBar(T : T*) { }
alias TBar!(char*) Foo3;        // (2) T is deduced to be char

Basically, what it means is that if a template parameter name is re-used as part of the specialization, it has the meaning of 'anything', and within the template, the identifier denotes what it represented within the specialization.

But where T is used as a template parameter in the specialization, I'm not sure it can work in the general case.  After all, there's a potential infinitude of templates to instantiate to try to find a match.  So I'm still not sure that the compiler should accept the template declaration.


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