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December 12, 2007 [Issue 1728] New: alias hides mixin member func? | ||||
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http://d.puremagic.com/issues/show_bug.cgi?id=1728 Summary: alias hides mixin member func? Product: D Version: 2.008 Platform: PC OS/Version: Windows Status: NEW Keywords: rejects-valid Severity: normal Priority: P2 Component: DMD AssignedTo: bugzilla@digitalmars.com ReportedBy: davidl@126.com import std.stdio; interface mix { void print(char[]); } template mixtem() { void print(char[] t) { writefln(t); } } class A { void print() { writefln("A"); } void print(int a) { writefln(a); } } class B:A,mix { alias A.print print; mixin mixtem; void pr() { super.print(); super.print(18); print("OK"); // this should call mixin member func writefln("B"); } } kk.d(36): function kk.A.print () does not match parameter types (char[2u]) -- |
June 26, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 davidl@126.com changed: What |Removed |Added ---------------------------------------------------------------------------- Keywords| |patch ------- Comment #1 from davidl@126.com 2008-06-25 23:18 ------- a patch in template.c TemplateMixin::semantic // Declare each template parameter as an alias for the argument type declareParameters(scope); ++ ScopeDsymbol *parent = sc -> parent; // Add members to enclosing scope, as well as this scope for (unsigned i = 0; i < members->dim; i++) { Dsymbol *s; s = (Dsymbol *)members->data[i]; +++ // for fixing bug 1728 http://d.puremagic.com/issues/show_bug.cgi?id=1728 +++ // actually we provide the sugar of introducing the funcdeclaration transparently from this anonymous scope +++ if (s -> isFuncDeclaration()) +++ { +++ s->addMember(scope, parent, i); +++ s->parent = this; +++ } +++ else s->addMember(scope, this, i); //sc->insert(s); //printf("sc->parent = %p, sc->scopesym = %p\n", sc->parent, sc->scopesym); //printf("s->parent = %s\n", s->parent->toChars()); } and in dsymbol.c: Dsymbol::addMember s2 = sd->symtab->lookup(ident); +++ s2 = s2 -> toAlias(); if (!s2->overloadInsert(this)) { sd->multiplyDefined(0, this, s2); } -- |
July 07, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 ------- Comment #2 from davidl@126.com 2008-07-07 08:36 ------- in the patch +++ if (s -> isFuncDeclaration()) +++ { +++ s->addMember(scope, parent, i); +++ s->parent = this; +++ } +++ else should be +++ if (s -> isFuncDeclaration() && parent != NULL ) +++ { +++ s->addMember(scope, parent, i); +++ s->parent = this; +++ } +++ else -- |
December 09, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 bugzilla@digitalmars.com changed: What |Removed |Added ---------------------------------------------------------------------------- Status|NEW |RESOLVED Resolution| |INVALID ------- Comment #3 from bugzilla@digitalmars.com 2008-12-09 05:13 ------- This is not a bug. The mixin establishes its own scope that is nested inside B's scope. If there is no print in B's scope, it will look in the mixin. If there is a print in B's scope, it will not look in the mixin. This works exactly the same as imports and symbols at module scope. The solution is to bring the desired members of mixtem up into B's scope. An alias will accomplish this, so rewriting B as: class B:A,mix { alias A.print print; mixin mixtem M; // give scope the name 'M' alias M.print print; // and bring M's print into B's scope void pr() { super.print(); super.print(18); print("OK"); // this should call mixin member func writefln("B"); } } should work. -- |
December 09, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 ------- Comment #4 from jarrett.billingsley@gmail.com 2008-12-09 07:18 ------- (In reply to comment #3) > This is not a bug. > > The mixin establishes its own scope that is nested inside B's scope. If there is no print in B's scope, it will look in the mixin. If there is a print in B's scope, it will not look in the mixin. > > This works exactly the same as imports and symbols at module scope. > > The solution is to bring the desired members of mixtem up into B's scope. That works fine for normal methods, but how about ctors? I actually ran into this. template mixtem() { this(char[] t) { Stdout.formatln(t); } } class A { mixin mixtem; this() { this("OK"); // same error as the OP } } Except of course "mixin mixtem M; alias M.this this;" is not legal. (I also tried using the weird _ctor but that doesn't work either.) -- |
December 10, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 ------- Comment #5 from bugzilla@digitalmars.com 2008-12-09 21:41 ------- I suspect that trying to make this work would add a bunch of arcane rules with little benefit. Instead, try to remove what this(string) does to a separate function, then call that function from the other this(). -- |
December 11, 2008 [Issue 1728] alias hides mixin member func? | ||||
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Posted in reply to d-bugmail | http://d.puremagic.com/issues/show_bug.cgi?id=1728 ------- Comment #6 from davidl@126.com 2008-12-11 06:19 ------- But I can't accept that: class B:A,mix { mixin mixtem; void pr() { print("OK"); // this should call mixin member func writefln("B"); } } works while: class B:A,mix { alias A.print print; mixin mixtem; void pr() { print("OK"); // this should call mixin member func writefln("B"); } } doesn't work. An alias shouldn't hide a func that I try to call. -- |
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