Thread overview
[Issue 3651] New: mangleof broken for enums
Dec 26, 2009
nfxjfg@gmail.com
Jan 14, 2010
mpiepk@gmail.com
Jan 28, 2010
Don
Jan 28, 2010
nfxjfg@gmail.com
Jan 28, 2010
Don
Jan 28, 2010
nfxjfg@gmail.com
May 31, 2010
Walter Bright
December 26, 2009
http://d.puremagic.com/issues/show_bug.cgi?id=3651

           Summary: mangleof broken for enums
           Product: D
           Version: 1.051
          Platform: Other
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody@puremagic.com
        ReportedBy: nfxjfg@gmail.com


--- Comment #0 from nfxjfg@gmail.com 2009-12-26 11:32:07 PST ---
First off, this bug report is for dmd 1.053, not 1.051; but bugzilla let's me only select up to 1.051.

.mangleof is broken for enums:

enum foo {
    item,
}

//should output a mangled name with "foo" in it, but outputs "i"
pragma(msg, foo.mangleof);

void main() {}

I apologize if this is a duplicate bug; there were quite a lot of enum bugs which look slightly similar (the compiler seems to reduce enums to ints prematurely in a lot of cases).

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January 14, 2010
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--- Comment #1 from mpiepk@gmail.com 2010-01-14 05:43:12 PST ---
Created an attachment (id=549)
Patch

Patch against dmd 1.055.
The problem is that mangleof is executed on the enum member type, not the enum
type itself.

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January 28, 2010
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Don <clugdbug@yahoo.com.au> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |clugdbug@yahoo.com.au


--- Comment #2 from Don <clugdbug@yahoo.com.au> 2010-01-28 00:47:21 PST ---
> enum foo {
>     item,
> }

> //should output a mangled name with "foo" in it, but outputs "i"
> pragma(msg, foo.mangleof);

Are you sure that's what it should do? Why do you think the existing behaviour is wrong?

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--- Comment #3 from nfxjfg@gmail.com 2010-01-28 00:55:57 PST ---
@Don: I'm pretty sure my bug report is correct. enums are the *only* type that behave different here. Further, if you get the mangle of a function or template that use enums as parameters, the enum gets mangled using the type name, not the base type.

Why do you think the current behavior would be correct? Why would .mangleof for a type return the mangle for a completely *different* type?

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--- Comment #4 from Don <clugdbug@yahoo.com.au> 2010-01-28 01:05:28 PST ---
(In reply to comment #3)
> @Don: I'm pretty sure my bug report is correct. enums are the *only* type that behave different here. Further, if you get the mangle of a function or template that use enums as parameters, the enum gets mangled using the type name, not the base type.
> 
> Why do you think the current behavior would be correct? Why would .mangleof for a type return the mangle for a completely *different* type?

Because enums aren't strong types. typeof(item) is int, not foo. 'foo' just
seems to be an alias for int. (I think the existing behaviour is stupid, BTW).

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--- Comment #5 from nfxjfg@gmail.com 2010-01-28 01:14:41 PST ---
>typeof(item) is int, not foo.

Even then, typeof(foo) is foo, and not int. It's only logical that foo.mangleof should be the mangle for foo, not int.

I don't know about item.mangelof. Is that even allowed?

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May 31, 2010
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Walter Bright <bugzilla@digitalmars.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |bugzilla@digitalmars.com
         Resolution|                            |FIXED


--- Comment #6 from Walter Bright <bugzilla@digitalmars.com> 2010-05-31 01:02:27 PDT ---
http://www.dsource.org/projects/dmd/changeset/508

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