1.c:
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>

int main(int argc, char *argv[])
{
unsigned long number = strtoul(argv[1], 0, 10);

if (errno)
{
perror("Incorrect integer value");
return 1;
}

printf("number = %lu\n", number);
return 0;
}

dmc 1.c & 1 abc
number = 0

Function strtoul doesn't set errno if the conversion can not be performed.

David

This is the correct behaviour according to the standard. (There is an erratum in the description of the function in my C book)

David

"David Grimes" <dgrimes@friberg.us> wrote in message news:c0p42c$2vfh$1@digitaldaemon.com...
> 1.c:
> #include <stdio.h>
> #include <stdlib.h>
> #include <errno.h>
>
> int main(int argc, char *argv[])
> {
> unsigned long number = strtoul(argv[1], 0, 10);
>
> if (errno)
> {
> perror("Incorrect integer value");
> return 1;
> }
>
> printf("number = %lu\n", number);
> return 0;
> }
>
> dmc 1.c & 1 abc
> number = 0
>
> Function strtoul doesn't set errno if the conversion can not be performed.
>
> David
>
>