Hello, there.

I was using function "toString()",  and found...

/* test.d */
import std.c.stdio;
import std.stream;

char* str;

void main(){
 for(int i=0; i<20; ++i){
  str = toString(i);
  printf("n=%s\n",str);
 }
 return;
}
/* end test.d */

result:
>test
n=0123456789
n=123456789
n=23456789
n=3456789
n=456789
n=56789
n=6789
n=789
n=89
n=9
n=10
n=11
n=12
n=13
n=14
n=15
n=16
n=17
n=18
n=19

Ozy wrote:
> Hello, there.
> 
> I was using function "toString()",  and found...
> 
> /* test.d */
> import std.c.stdio;
> import std.stream;
> 
> char* str;
> 
> void main(){
>  for(int i=0; i<20; ++i){
>   str = toString(i);
>   printf("n=%s\n",str);
>  }
>  return;
> }
> /* end test.d */
> 
> result:
> 
>>test
> 
> n=0123456789
> n=123456789
> n=23456789
> n=3456789
> n=456789
> n=56789
> n=6789
> n=789
> n=89
> n=9
> n=10
> n=11
> n=12
> n=13
> n=14
> n=15
> n=16
> n=17
> n=18
> n=19

Interesting, but not entirely unexpected.

This might be what you want:

/* test.d */
import std.c.stdio;
import std.stream;

char[] str;
/* I wouldn't use a char* unless I had to. */

void main(){
 for(int i=0; i<20; ++i){
  str = toString(i);
  printf("n=%.*s\n",str);
/* "%.*s" is the specifier for char[]*/
 }
 return;
}
/* end test.d */

n=0
n=1
n=2
n=3
n=4
n=5
n=6
n=7
n=8
n=9
n=10
n=11
n=12
n=13
n=14
n=15
n=16
n=17
n=18
n=19

There are a couple reasons for this:
1) toString expects to to return a char[].
2) Weird things can happen when strings are sent to printf without a trailing \0.

For some more interesting examples, see: http://www.prowiki.org/wiki4d/wiki.cgi?HowTo/printf


-- 
Justin (a/k/a jcc7)
http://jcc_7.tripod.com/d/

Ozy wrote:
> /* test.d */
> import std.c.stdio;
> import std.stream;
> 
> char* str;
> 
> void main(){
>  for(int i=0; i<20; ++i){
>   str = toString(i);
>   printf("n=%s\n",str);
>  }
>  return;
> }
> /* end test.d */


Hiya, your programs has several programs... you're using char* to point to a string. after doing str=toString() you loose the length of the string and you cant give it thru %.*s to printf. and you give it thru normal %s which doesnt work with D strings...

The solution is damn simple, though :]

!(code)
import std.stdio;

void main()
{
    for (int i = 0; i < 20; ++i)
    {
        writefln("n=", i);
    }
}
!(/code)

printf should be depreceated for new code imo ;)


Tom

On Thu, 12 Aug 2004 11:51:18 +0900, Ozy wrote:

> Hello, there.
> 
> I was using function "toString()",  and found...
> 
> /* test.d */
> import std.c.stdio;
> import std.stream;
> 
> char* str;
> 
> void main(){
>  for(int i=0; i<20; ++i){
>   str = toString(i);
>   printf("n=%s¥n",str);
>  }
>  return;
> }
> /* end test.d */
> 
> result:
>>test
> n=0123456789
> n=123456789
> n=23456789
> n=3456789
> n=456789
> n=56789
> n=6789
> n=789
> n=89
> n=9
> n=10
> n=11
> n=12
> n=13
> n=14
> n=15
> n=16
> n=17
> n=18
> n=19

If the integer is from 0 to 9, the toString() routine returns a slice into a static array. The correct way to use the return value from toString is more like this ...

import std.c.stdio;
import std.stream;

char[] str; // NOT char*;

void main(){
  for(int i=0; i<20; ++i)
  {
   str = toString(i);
   printf("n=%.*s\n",str);  // NOT %s but %.*s
  }
  return;
 }
 /* end test.d */


-- 
Derek
Melbourne, Australia
12/Aug/04 1:48:11 PM

I see.
Then, if I use C-Library, should I write like this?

char[2] str;
str[0] = toString(0-9numeral)[0];
str[1] ='\0';

c_func(str);

It's troublesome for me...

Anyway, I understood that this problem is not a bug.
Thank you very much!

"Ozy" <ozy@4dm.org> wrote in message news:cfeu67$1pk3$1@digitaldaemon.com...
> I see.
> Then, if I use C-Library, should I write like this?
>
> char[2] str;
> str[0] = toString(0-9numeral)[0];
> str[1] ='\0';
>
> c_func(str);
>
> It's troublesome for me...
>
> Anyway, I understood that this problem is not a bug.
> Thank you very much!


char[] dstr;
char* cstr;

dstr = toString(9);
cstr = toStringz(dstr); // zero terminate

c_func(cstr); // hooray

I felt sad to know my silliness.....(ToT)
Thank you!