void main()
{
        char[] s;
        char[] t;

        if (true)
            s = null;
        s = (true) ? null : t;
}

"test.d(8): cannot implicitly convert expression (1 ? null : cast(void*)(t))
of type void* to char[]"

You could be forgiven for thinking the error is talking about 't'. But it's actually talking about the assignment of null instead. This works as expected:

s = (true) ? cast(char[]) null : t;

But you've got to explicitly cast the null. Yet, the "more traditional" assignment, on line 7, is accepted without error. What's the deal here?

Yeah, that ain't right. I'll fix it.

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Hash: SHA1

Kris schrieb am Fri, 8 Apr 2005 22:33:34 -0700:
> void main()
> {
>         char[] s;
>         char[] t;
>
>         if (true)
>             s = null;
>         s = (true) ? null : t;
> }
>
> "test.d(8): cannot implicitly convert expression (1 ? null : cast(void*)(t))
> of type void* to char[]"
>
> You could be forgiven for thinking the error is talking about 't'. But it's actually talking about the assignment of null instead. This works as expected:
>
> s = (true) ? cast(char[]) null : t;
>
> But you've got to explicitly cast the null. Yet, the "more traditional" assignment, on line 7, is accepted without error. What's the deal here?

Added to DStress as
http://dstress.kuehne.cn/run/cast_25.d
http://dstress.kuehne.cn/run/cast_26.d
http://dstress.kuehne.cn/run/cast_27.d

Thomas


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