One of the differences between D and C seems
to be that I am able to call D functions without
parameters by simply omitting the empty
brackets:

So
         test();
or
         test;
will give equivalent results.

In C only the first statement will work. The
other one will result in a warning and otherwise
gets ignored.

I am lazy enough to like the idea that I can
omit the brackets if I'd wish to, but I also
want to ensure that future versions of dmd
will still allow me to do that.

???

"Bob W" <nospam@aol.com> wrote in message news:ds8k29$qt0$1@digitaldaemon.com...
> I am lazy enough to like the idea that I can
> omit the brackets if I'd wish to, but I also
> want to ensure that future versions of dmd
> will still allow me to do that.

This is a result of the "implicit property syntax" in D, which is a feature, and which doesn't seem to be going away.  So don't worry :)

"Jarrett Billingsley" <kb3ctd2@yahoo.com> wrote in message news:ds8nfc$t5o$1@digitaldaemon.com...
> "Bob W" <nospam@aol.com> wrote in message news:ds8k29$qt0$1@digitaldaemon.com...
>> I am lazy enough to like the idea that I can
>> omit the brackets if I'd wish to, but I also
>> want to ensure that future versions of dmd
>> will still allow me to do that.
>
> This is a result of the "implicit property syntax" in D, which is a feature, and which doesn't seem to be going away.  So don't worry :)


I won't, thanks.

Jarrett Billingsley wrote:
> "Bob W" <nospam@aol.com> wrote in message news:ds8k29$qt0$1@digitaldaemon.com...
>> I am lazy enough to like the idea that I can
>> omit the brackets if I'd wish to, but I also
>> want to ensure that future versions of dmd
>> will still allow me to do that.
> 
> This is a result of the "implicit property syntax" in D, which is a feature, and which doesn't seem to be going away.  So don't worry :) 

I've always been a bit unsure about this.  Firstly, it _looks_ like an effectless (and therefore illegal) statement, and as such is likely to arouse the suspicion of anybody who reads the code.  Secondly, I had previously got the impression that, when you use a function name, you had to do one of the following with it:

- assign to it
- use it as an rvalue in an expression
- take its address

Using it on its own for an ExpressionStatement isn't doing any of these, and so there's nothing disambiguating how the function name is being used.

Stewart.

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