Thread overview
Variadic Templates or functions with Lazy Evalutaion
Aug 14, 2007
convert
Aug 14, 2007
Daniel919
August 14, 2007
I am trying to write a log function that can take a variable number of arguments and does lazy evaluation on each of them.

-------------
void log(A...) (int level ,lazy A args)
{
    if(level > 1) Stdout(args).newline();
}

log(2, "Hello");

-----------

Produces:

test2.d(22): template instance test2.log!(char[6u]) error instantiating
test2.d(22): Error: functions cannot return static array char[6u]

And

void log(int level ,lazy ...)

produces:

test2.d(15): basic type expected, not ...

Should any of these work?

August 14, 2007
void test(T)(lazy T arg)
{
	writefln(arg);
}
test("abc");


is converted to:


void test(string delegate() arg)
{
	writefln(arg);
}
test({return "abc"});


So we have:
string delegate() arg = {return "abc"};

And this is related to bug #1371:

//string delegate() dg = { return "dg"; };
//Error: functions cannot return static array invariant char[2u]

string delegate() dg = delegate string() { return "dg"; }; //OK
auto dg = { return "dg".dup; }; //OK
string fn() { return "fn"; }; //OK




However this is working:
void test(T)(lazy T arg)
{
	writefln(arg);
}
test("abc".dup);



For simple logging you could also use this:
void log(args...)() {
	if (args[0] > 1)
		writefln(args[1..$]);
}
log!(2, "abc", "def")();

Remember that you can't use runtime functions/data then:
log!(2, runtimeprocessingfunction("abc"));
//Error: cannot evaluate runtimeprocessingfunction("abc") at compile time

log!(2, compiletimefunction("abc")); //OK


Best regards,
Daniel
August 14, 2007
convert wrote:
> I am trying to write a log function that can take a variable number of arguments and does lazy evaluation on each of them.
> 
> -------------
> void log(A...) (int level ,lazy A args)
> {
>     if(level > 1) Stdout(args).newline();
> }
> 
> log(2, "Hello");
> 
> -----------
> 
> Produces:
> 
> test2.d(22): template instance test2.log!(char[6u]) error instantiating
> test2.d(22): Error: functions cannot return static array char[6u]

In this case, the problem is that string literals are always static/fixed-length arrays, which cannot be returned from functions -- and lazy parameters are "on the fly" wrapped as delegate functions.  Ie, the parameter 'lazy int' is typed the same as 'int delegate()'.

It will work as written if you pass a full-slice of the literal -- or if the value is in a dynamic/variable-length array to begin with.
    log(2, "Hello"[]);

This isn't so bad unless you intend to have several literal strings in a call to log... then it gets a little awkward looking.
    log(2, "Hello"[], "from"[], "D"[]);

> And
> 
> void log(int level ,lazy ...)
> 
> produces:
> 
> test2.d(15): basic type expected, not ...
> 
> Should any of these work?
> 

This will not work because of the way (as I mentioned earlier) lazy parameters are re-written as delegates.  A function must have a formal return type.

-- Chris Nicholson-Sauls