How do I iterate through an AA sorted by key?

I am unable to .dup the aa.byKeyValue().

I have tried both
foreach(e; aa.byKeyValue().sort!"a.key < b.key")
{
    //... use e. key && e.value
}

and

foreach(k,v; aa.byKeyValue().sort!"a.key < b.key")
{

}

i get :
template std.algorithm.sorting.sort cannot deduce function from argument types !("a.key < b.key")(Result), candidates are:
std/algorithm/sorting.d(875):        std.algorithm.sorting.sort(alias less = "a < b", SwapStrategy ss = SwapStrategy.unstable, Range)(Range r) if ((ss == SwapStrategy.unstable && (hasSwappableElements!Range || hasAssignableElements!Range) || ss != SwapStrategy.unstable && hasAssignableElements!Range) && isRandomAccessRange!Range && hasSlicing!Range && hasLength!Range)

any clues?

On Sat, Jun 27, 2015 at 12:22:06PM +0000, Nicholas Wilson via Digitalmars-d-learn wrote:
> How do I iterate through an AA sorted by key?
> 
> I am unable to .dup the aa.byKeyValue().

Because it is a range, not an array.

To turn it into an array, write:

	aa.byKeyValue().array.sort!"a.key < b.key"


T

-- 
Three out of two people have difficulties with fractions. -- Dirk Eddelbuettel

On Saturday, 27 June 2015 at 12:27:59 UTC, H. S. Teoh wrote:
> On Sat, Jun 27, 2015 at 12:22:06PM +0000, Nicholas Wilson via Digitalmars-d-learn wrote:
>> How do I iterate through an AA sorted by key?
>> 
>> I am unable to .dup the aa.byKeyValue().
>
> Because it is a range, not an array.
>
> To turn it into an array, write:
>
> 	aa.byKeyValue().array.sort!"a.key < b.key"
>
>
> T

Derp.

Thankyou!