Is there a way to give default types to template tuple parameters?
Like this:


class Test (TTuple ... = [char, int] )
{
	// ...
}

void main ()
{
	Test t; // Equivalent to Test !(char, int) t;
}


Obviously, that does not compile.

Thanks in advance,
-Peter

On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer <peterneubauer2@gmail.com> wrote:

> Is there a way to give default types to template tuple parameters?
> Like this:
>
>
> class Test (TTuple ... = [char, int] )
> {
> 	// ...
> }
>
> void main ()
> {
> 	Test t; // Equivalent to Test !(char, int) t;
> }
>
>
> Obviously, that does not compile.
>
> Thanks in advance,
> -Peter

This oughtta work (does on my confuser).


  import std.typetuple;

  class Test (TTuple ... = TypeTuple!(char, int) )
  {
	// ...
  }

  void main ()
  {
	Test t; // Equivalent to Test !(char, int) t;
  }


-- Simen

Simen Kjaeraas schrieb:
> On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer <peterneubauer2@gmail.com> wrote:
> 
>> Is there a way to give default types to template tuple parameters?
>> Like this:
>>
>>
>> class Test (TTuple ... = [char, int] )
>> {
>>     // ...
>> }
>>
>> void main ()
>> {
>>     Test t; // Equivalent to Test !(char, int) t;
>> }
>>
>>
>> Obviously, that does not compile.
>>
>> Thanks in advance,
>> -Peter
> 
> This oughtta work (does on my confuser).
> 
> 
>   import std.typetuple;
> 
>   class Test (TTuple ... = TypeTuple!(char, int) )
>   {
>     // ...
>   }
> 
>   void main ()
>   {
>     Test t; // Equivalent to Test !(char, int) t;
>   }
> 
> 
> -- Simen

Strange, all I get is this:

test.d(3): found '=' when expecting ')'
test.d(3): { } expected following aggregate declaration
test.d(3): no identifier for declarator TypeTuple!(char,int)
test.d(3): semicolon expected, not ')'
test.d(3): Declaration expected, not ')'

Maybe this is a difference between D 1.0 and 2.0? (I'm using 1.0)

-Peter

On Mon, 31 Mar 2008 01:29:10 +0200, Peter Neubauer <peterneubauer2@gmail.com> wrote:

> Simen Kjaeraas schrieb:
>> On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer <peterneubauer2@gmail.com> wrote:
>>
>>> Is there a way to give default types to template tuple parameters?
>>> Like this:
>>>
>>>
>>> class Test (TTuple ... = [char, int] )
>>> {
>>>     // ...
>>> }
>>>
>>> void main ()
>>> {
>>>     Test t; // Equivalent to Test !(char, int) t;
>>> }
>>>
>>>
>>> Obviously, that does not compile.
>>>
>>> Thanks in advance,
>>> -Peter
>>  This oughtta work (does on my confuser).
>>     import std.typetuple;
>>    class Test (TTuple ... = TypeTuple!(char, int) )
>>   {
>>     // ...
>>   }
>>    void main ()
>>   {
>>     Test t; // Equivalent to Test !(char, int) t;
>>   }
>>   -- Simen
>
> Strange, all I get is this:
>
> test.d(3): found '=' when expecting ')'
> test.d(3): { } expected following aggregate declaration
> test.d(3): no identifier for declarator TypeTuple!(char,int)
> test.d(3): semicolon expected, not ')'
> test.d(3): Declaration expected, not ')'
>
> Maybe this is a difference between D 1.0 and 2.0? (I'm using 1.0)
>
> -Peter


Tested it again. Appears I did get part of it wrong.

	class test(TTuple = TypeTuple!(char, int))

That works. Without the ellipsis. However, that is of course not what you wanted.
I do agree it should, though.

--Simen