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August 15, 2008 Subclass Type | ||||
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Hi, does anyone know how to return a Subclass's type? I would like to create a new instance of the subclass based on its type. Here is my example code.... class FooBar { class Foo : FooBar { this() { super(1); } override void printKey() { Stdout(key).newline; } } class Bar : FooBar { this() { super(2); } override void printKey() { Stdout(key).newline; } } void main() { FooBar x = new Foo(); FooBar y = new typeof(x); x.key++; y.printKey(); // This prints 0. I want it to print 1 } As is, y is created as type FooBar. Instead I would like to be of type Foo. i.e the equivalent of: FooBar y = new Foo(); I've seen this done in other languages such as ActionScript fairly easily: public function createJoint(data:JointData):Joint { var c:Class = data.getJointClass(); var j:Joint = new c(data) as Joint; } In this case, Joint is the superclass. data.getJointClass returns the subclass type. j is created as a new subclass. The normal D equivalent would be: Joint j = new MouseJoint(); // or some other subclass that getJointClass // returns. Thanks, Mason |
August 15, 2008 Re: Subclass Type | ||||
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Posted in reply to Mason Green | Damn, my code was cut off.... here it is again... class FooBar { int key; this() { } this(int key) { this.key = key; } void printKey() { Stdout(key).newline; } } class Foo : FooBar { this() { super(1); } override void printKey() { Stdout(key).newline; } } class Bar : FooBar { this() { super(2); } override void printKey() { Stdout(key).newline; } } void main() { FooBar x = new Foo(); FooBar y = new typeof(x); x.key++; y.printKey(); // This prints 0. I want it to print 1 } |
August 15, 2008 Re: Subclass Type | ||||
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Posted in reply to Mason Green | "Mason Green" <mason.green@gmail.com> wrote in message news:g83tfo$k14$1@digitalmars.com... > Hi, does anyone know how to return a Subclass's type? I would like to create a new instance of the subclass based on its type. Here is my example code.... > > class FooBar { > > > class Foo : FooBar { > > this() { > super(1); > } > > override void printKey() { > Stdout(key).newline; > } > > } > > class Bar : FooBar { > > this() { > super(2); > } > > override void printKey() { > Stdout(key).newline; > } > } > > void main() { > > FooBar x = new Foo(); > FooBar y = new typeof(x); > > x.key++; > y.printKey(); // This prints 0. I want it to print 1 > > } > > As is, y is created as type FooBar. Instead I would like to be of type Foo. i.e the equivalent of: > > FooBar y = new Foo(); > > I've seen this done in other languages such as ActionScript fairly easily: > > public function createJoint(data:JointData):Joint > { > var c:Class = data.getJointClass(); > var j:Joint = new c(data) as Joint; > } > > In this case, Joint is the superclass. data.getJointClass returns the subclass type. j is created as a new subclass. The normal D equivalent would be: > > Joint j = new MouseJoint(); // or some other subclass that getJointClass > // returns. > > Thanks, > Mason You can't, at least not easily. It's easy in ActionScript because it's a dynamic, introspective language. D is statically-typed, and since you can't know what subclass something is until runtime, you can't know what static type to use for it. There is Object.factory, which allows you to create an instance of a class from its name, but it's extremely restrictive -- the class must have a no-argument constructor (or use only the automatically-generated no-argument constructor). In your particular situation, you could put an abstract "dup" (duplicate) method in FooBar and implement it in Foo and Bar, so that if you have one instance of a subclass, you can create another instance of the same class by dup'ing it. But in general, runtime type identification is not going to get you very far in D. This doesn't mean you can't solve your problems, it just means you'll have to solve them a different way. |
August 17, 2008 Re: Subclass Type | ||||
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Posted in reply to Jarrett Billingsley | Jarrett Billingsley Wrote: > You can't, at least not easily. It's easy in ActionScript because it's a dynamic, introspective language. D is statically-typed, and since you can't know what subclass something is until runtime, you can't know what static type to use for it. Ah, excellent explanation. Thanks! > But in general, runtime type identification is not going to get you very far in D. This doesn't mean you can't solve your problems, it just means you'll have to solve them a different way. > I know how to get around solving the problem, I was just hoping that there was a "quick and easy" way. In any case, I appreciate your explanation and suggestion. Thanks, Mason |
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