how do i convert a string of chars to byte array

will this work:

ubyte[] b;
char[] s="test";
b = cast(ubyte[]) s;

thx in advance

Reply to rickdiaz,

> how do i convert a string of chars to byte array
> 
> will this work:
> 
> ubyte[] b;
> char[] s="test";
> b = cast(ubyte[]) s;
> thx in advance
> 

yes

Reply to rickdiaz,

> how do i convert a string of chars to byte array
> 
> will this work:
> 
> ubyte[] b;
> char[] s="test";
> b = cast(ubyte[]) s;
> thx in advance
> 

note: char[] is utf-8 so that might not do exactly what you expect if you are not careful about what you expect.

BCS Wrote:

> Reply to rickdiaz,
> 
> > how do i convert a string of chars to byte array
> > 
> > will this work:
> > 
> > ubyte[] b;
> > char[] s="test";
> > b = cast(ubyte[]) s;
> > thx in advance
> > 
> 
> note: char[] is utf-8 so that might not do exactly what you expect if you are not careful about what you expect.
> 
> 

i wonder how you turn uint into ubyte array?, because above method wont work

"james" wrote
> BCS Wrote:
>
>> Reply to rickdiaz,
>>
>> > how do i convert a string of chars to byte array
>> >
>> > will this work:
>> >
>> > ubyte[] b;
>> > char[] s="test";
>> > b = cast(ubyte[]) s;
>> > thx in advance
>> >
>>
>> note: char[] is utf-8 so that might not do exactly what you expect if you are not careful about what you expect.
>>
>>
>
> i wonder how you turn uint into ubyte array?, because above method wont work

uint i;
auto ubarray = (cast(ubyte *)&i)[0..i.sizeof];

But be careful, you have to account for endianness.

-Steve

Steven Schveighoffer Wrote:

> "james" wrote
> > BCS Wrote:
> >
> >> Reply to rickdiaz,
> >>
> >> > how do i convert a string of chars to byte array
> >> >
> >> > will this work:
> >> >
> >> > ubyte[] b;
> >> > char[] s="test";
> >> > b = cast(ubyte[]) s;
> >> > thx in advance
> >> >
> >>
> >> note: char[] is utf-8 so that might not do exactly what you expect if you are not careful about what you expect.
> >>
> >>
> >
> > i wonder how you turn uint into ubyte array?, because above method wont work
> 
> uint i;
> auto ubarray = (cast(ubyte *)&i)[0..i.sizeof];
> 
> But be careful, you have to account for endianness.
> 
> -Steve
> 
> 
 thanks alot