I am using the function pow() from std.math but if I try pow(2, 32) it returns 0, it doesn't compute beyond the maximum value of an int(2^31) and I am working with long. What should I do?

On Thursday, 29 November 2018 at 07:07:06 UTC, Murilo wrote:
> I am using the function pow() from std.math but if I try pow(2, 32) it returns 0, it doesn't compute beyond the maximum value of an int(2^31) and I am working with long. What should I do?

what exactly is your input?

´´´
import std.stdio;
import std.experimental.all;

void main()
{
	long u = 2;
	assert(pow(u,32) == 4294967296);
	assert(pow(2UL,32) == 4294967296);
}
´´´

On Thu, Nov 29, 2018 at 8:10 AM Murilo via Digitalmars-d-learn < digitalmars-d-learn@puremagic.com> wrote:

> I am using the function pow() from std.math but if I try pow(2,
> 32) it returns 0, it doesn't compute beyond the maximum value of
> an int(2^31) and I am working with long. What should I do?
>

if you look at doc: https://dlang.org/phobos/std_math.html#.pow.2

you will see that return type is infered from pow arguments, so if both arguments are int for example the return value would be int too https://run.dlang.io/is/FMVJhY

so if you want to have long as output one of your args should be (u)long or
you can enforce that by
pow!long(2,32);

https://run.dlang.io/is/WlDfsE

Hi guys, thank you for helping me out here, there is this facebook group for the D language, here we can help and teach each other. It is called Programming in D. Please join. https://www.facebook.com/groups/662119670846705/?ref=bookmarks