Is there any reason why

mixin template Foo(T)
{

}

Struct Bar(ailas a)
{
    mixin a!int
}

doesn't work?
It gives an error saying that mixin templates are not normal templates.
I hacked around this by making Bar take an enumeration and then "static switch"ing on it to select the correct mixin template, but that makes the set of mixins i can pass it closed.

It needs to be a mixin template because I need to access Bar's this from inside Foo.

On Friday, 25 November 2016 at 00:43:25 UTC, Nicholas Wilson wrote:

works like a charm:


mixin template Foo(T) {
  int z = 42;
}

auto Bar(alias a) () {
  mixin a!int;
  return z;
}

void main () {
  writeln(Bar!Foo);
}

On Friday, 25 November 2016 at 01:08:38 UTC, ketmar wrote:
> On Friday, 25 November 2016 at 00:43:25 UTC, Nicholas Wilson wrote:
>
> works like a charm:
>
>
> mixin template Foo(T) {
>   int z = 42;
> }
>
> auto Bar(alias a) () {
>   mixin a!int;
>   return z;
> }
>
> void main () {
>   writeln(Bar!Foo);
> }

Hmm, maybe i was trying to do Bar!Foo!int ...