icon = *(toStringz(text(num)));

icon is a char, num is an integer.
I don't suppose there is an easier way to do this?

It's too late and ma brains is mushy.

On Sat, 05 Nov 2011 10:29:36 +0200, Jude Young <10equals2@gmail.com> wrote:

> icon = *(toStringz(text(num)));
>
> icon is a char, num is an integer.
> I don't suppose there is an easier way to do this?
>
> It's too late and ma brains is mushy.

If I understood the problem correctly:

icon = text(num)[0];

-- or --

icon = cast(char)('0' + num);

-- 
Best regards,
 Vladimir                            mailto:vladimir@thecybershadow.net

Jude Young:

> icon = *(toStringz(text(num)));
> 
> icon is a char, num is an integer.

Are you trying to convert a single-digit number?

import std.stdio;
void main() {
    int x = 5; // in [0 .. 10]
    char c = cast(char)(x + '0');
    writeln(c);
}

Bye,
bearophile

Nice.  Exactly what I was looking for.
I knew I was missing something tiny.

Now I just need to figure out why that works and I can say I've learned
something!
Thanks guys,
Jude

On Sat, Nov 5, 2011 at 5:38 AM, bearophile <bearophileHUGS@lycos.com> wrote:

> Jude Young:
>
> > icon = *(toStringz(text(num)));
> >
> > icon is a char, num is an integer.
>
> Are you trying to convert a single-digit number?
>
> import std.stdio;
> void main() {
>    int x = 5; // in [0 .. 10]
>    char c = cast(char)(x + '0');
>    writeln(c);
> }
>
> Bye,
> bearophile
>

On Sun, 06 Nov 2011 04:39:28 -0000, Jude Young <10equals2@gmail.com> wrote:
> Nice.  Exactly what I was looking for.
> I knew I was missing something tiny.
>
> Now I just need to figure out why that works and I can say I've learned
> something!
> Thanks guys,
> Jude
>
> On Sat, Nov 5, 2011 at 5:38 AM, bearophile <bearophileHUGS@lycos.com> wrote:
>
>> Jude Young:
>>
>> > icon = *(toStringz(text(num)));
>> >
>> > icon is a char, num is an integer.
>>
>> Are you trying to convert a single-digit number?
>>
>> import std.stdio;
>> void main() {
>>    int x = 5; // in [0 .. 10]
>>    char c = cast(char)(x + '0');
>>    writeln(c);
>> }

You've also got std.ascii.digits which is "0123456789" and std.string.digits which is an alias of it, so you can say:

import std.ascii; (or std.string)

int x = 5;
char c = std.ascii.digits[x];

-- 
Using Opera's revolutionary email client: http://www.opera.com/mail/

Regan Heath wrote:

> You've also got std.ascii.digits which is "0123456789" and std.string.digits which is an alias of it, so you can say:
> 
> import std.ascii; (or std.string)
> 
> int x = 5;
> char c = std.ascii.digits[x];
> 

I used similar solution to bearophile's before. I must admit i did not know about std.ascii.digits[], thanks for the info Regan.