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A function to split a range into several ranges of different chunks
Sep 14
Seb
-----
import std.range;
import std.stdio;

void main ()
{
auto range = sequence!((a, n) => n);

// works, but the chunks are all the same length
auto rngs = range.chunks(4);
writeln(rngs[0]);
writeln(rngs[1]);
writeln(rngs[2]);

// want this
auto ranges = range.???(3, 4, 5);
writeln(ranges[0] == [1, 2, 3]);
writeln(ranges[1] == [4, 5, 6, 7]);
writeln(ranges[2] == [8, 9, 10, 11, 12]);
}
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Do you know of a simple way to do this? It's essentially similar to chunks, except the chunks themselves would not be of the same length.

You can think of a good name for '???' here. Maybe this is already possible by combining functionality in std.range - but I came up short.
On Monday, 14 September 2020 at 07:49:31 UTC, Andrej Mitrovic wrote:
> -----
> import std.range;
> import std.stdio;
>
> void main ()
> {
>     auto range = sequence!((a, n) => n);
>
>     // works, but the chunks are all the same length
>     auto rngs = range.chunks(4);
>     writeln(rngs[0]);
>     writeln(rngs[1]);
>     writeln(rngs[2]);
>
>     // want this
>     auto ranges = range.???(3, 4, 5);
>     writeln(ranges[0] == [1, 2, 3]);
>     writeln(ranges[1] == [4, 5, 6, 7]);
>     writeln(ranges[2] == [8, 9, 10, 11, 12]);
> }
> -----
>
> Do you know of a simple way to do this? It's essentially similar to chunks, except the chunks themselves would not be of the same length.
>
> You can think of a good name for '???' here. Maybe this is already possible by combining functionality in std.range - but I came up short.

You likely want to get involved / raise your support here:

https://github.com/dlang/phobos/pull/7600
On Monday, 14 September 2020 at 09:08:01 UTC, Seb wrote:
> You likely want to get involved / raise your support here:
>
> https://github.com/dlang/phobos/pull/7600

Oh this is great, thank you!