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January 17, 2016 function argument accepting function or delegate? | ||||
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My underlying question is how to compose functions taking functions as arguments, while allowing the caller the flexibility to pass either a function or delegate. Simply declaring an argument as either a function or delegate seems to prohibit the other. Overloading works. Are there better ways? An example: auto callIntFn (int function(int) f, int x) { return f(x); } auto callIntDel (int delegate(int) f, int x) { return f(x); } auto callIntFnOrDel (int delegate(int) f, int x) { return f(x); } auto callIntFnOrDel (int function(int) f, int x) { return f(x); } void main(string[] args) { alias AddN = int delegate(int); AddN makeAddN(int n) { return x => x + n; } auto addTwo = makeAddN(2); // Delegate int function(int) addThree = x => x + 3; // Function // assert(callIntFn(addTwo, 4) == 6); // Compile error // assert(callIntDel(addThree, 4) == 7); // Compile error assert(callIntDel(addTwo, 4) == 6); assert(callIntFn(addThree, 4) == 7); assert(callIntFnOrDel(addTwo, 4) == 6); assert(callIntFnOrDel(addThree, 4) == 7); } ---Jon |
January 17, 2016 Re: function argument accepting function or delegate? | ||||
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Posted in reply to Jon D | On Sunday, 17 January 2016 at 06:27:41 UTC, Jon D wrote:
> My underlying question is how to compose functions taking functions as arguments, while allowing the caller the flexibility to pass either a function or delegate.
>
> [...]
Templates are an easy way.
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auto call(F, Args...)(F fun, auto ref Args args) { return fun(args); }
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Would probably look nicer with some constraints from std.traits.
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January 17, 2016 Re: function argument accepting function or delegate? | ||||
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Posted in reply to rsw0x | On Sunday, 17 January 2016 at 06:49:23 UTC, rsw0x wrote:
> On Sunday, 17 January 2016 at 06:27:41 UTC, Jon D wrote:
>> My underlying question is how to compose functions taking functions as arguments, while allowing the caller the flexibility to pass either a function or delegate.
>>
>> [...]
>
> Templates are an easy way.
>
> ---
> auto call(F, Args...)(F fun, auto ref Args args) { return fun(args); }
> ---
> Would probably look nicer with some constraints from std.traits.
Thanks much, that works!
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January 22, 2016 Re: function argument accepting function or delegate? | ||||
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Posted in reply to Jon D | On 1/17/16 1:27 AM, Jon D wrote:
> My underlying question is how to compose functions taking functions as
> arguments, while allowing the caller the flexibility to pass either a
> function or delegate.
>
> Simply declaring an argument as either a function or delegate seems to
> prohibit the other. Overloading works. Are there better ways?
If you are looking for a runtime way to do this (the template alias way works too), you may look at std.functional.toDelegate which converts a function pointer to a delegate.
But it is awkward to make this a requirement for your user.
-Steve
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